@文心快码dart string 转json 文心快码 在Dart中,将字符串转换为JSON对象通常使用dart:convert库中的jsonDecode函数。下面我将详细解释如何在Dart中将字符串解析为JSON对象,并处理可能出现的解析错误。 1. 导入dart:convert库 首先,需要导入dart:convert库,这是Dart内置的库,用于处理JSON和UTF
String toJson() => json.encode(toMap()); factory User.fromJson(String source) => User.fromMap(json.decode(source)); @override String toString() { return 'User(id: $id, userId: $userId, userMobile: $userMobile, userPassword: $userPassword, userNickname: $userNickname, userAvatar: $u...
toDate: 31-12-2021}}，{name: Peter，phoneNumber: 9999999999，userPost：{_id: 61896ccafcaa832828...
varjsonText = jsonEncode(scores); print(jsonText); } 使用对象添加模板JSON to Dart import'dart:convert'; classMyInfo{ MyInfo({this.age,this.name}); Stringname; intage; factoryMyInfo.fromJson(Map<String,dynamic> jsonMap) { returnMyInfo( name: jsonMap['name'], age: jsonMap['age'], ...
wheels); } void main() { final jsonString = Vehicle('bicycle', 2).toJson(); print('Vehicle serialized: $jsonString'); } 那么它是怎样工作的? toJson()/ fromJson() 是从哪里来的?这就是 Dart Macros 的支持,当 Dart 编译器看到 @JsonCodable() 注释时,它会立即实时定位到 JsonCodable 宏的...
Map<String, dynamic> toJson() { final Map<String, dynamic> data = new Map<String, dynamic>(); data['username'] = username; data['isVip'] = isVip; return data; } } 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. ...
jsonEncode will actually try to call toJson on the class if it's not a type that it recognizes. Colloquially we expect this to return a Map instead of an encoded json string. dart_mappable does not match dart conventions in this regard, and you end up with a situation like this...
代码的实现很简单,首先看 bin 下的示例,通过@Model()将GetUsersResponse和User声明为 JSON 对象,然后在运行时,宏编程会自动添加fromJson和toJson方式。 import'dart:convert';import'package:macros/model.dart';@Model()classUser{User({requiredthis.username,requiredthis.password,});finalStringusernam...
factory Author.fromJson(Map<String, dynamic> json) => _$AuthorFromJson(json); Map<String,dynamic> toJson() => _$AuthorToJson(this); } 这里有几点需要注意的 1、当我们初次创建Author.dart的时候,需要加入 part 'Author.g.dart'; 虽然系统会提示报错,但是不必紧张,这个我们一会生成Author.g.dart文...
classJsonModelDemo{Stringkey;Stringvalue;/// jsonDecode(jsonStr) 方法中会调用实体类的这个方法。如果实体类中没有这个方法,会报错。MaptoJson(){ Map map =newMap(); map["key"] =this.key; map["value"] =this.value;returnmap; } }