Detect cycle in undirected graph: method 1: Union FindThe time complexity of the union-find algorithm is O(ELogV).
int[][] edges = {{0, 1}, {1, 2}, {2, 0}}; boolean result = so.hasCycleDirectedGraph(3, edges); System.out.println(result); } } Detect Cycle in Undirected Graph 无向图找环 Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of n...
Detect cycle in an undirected graph https://www.geeksforgeeks.org/detect-cycle-undirected-graph/ 无向图就简单很多,如果dfs的时候,当前节点的neighbor中有被访问过且不是parent的节点,就一定有环存在。 这里顺便复习一下dfs两种写法:1) dfs最开始判断边界条件 2) dfs前判断边界条件 由于需要dfs时判断是否是p...
Given a linked list, determine if it has a cycle in it.Follow up:Can you solve it without using extra space? 1 public class Solution { 2 public boolean hasCycle(ListNode head) { 3 // IMPORTANT: Please reset any member data you declared, as 4 // the same Solution instance will be ....
Given a linked list, determine if it has a cycle in it. Follow up: Can you solve it without using extra space? Solution: solve the problem with one and two steps no cycle case: the faster pointer(two step) reaches the null first ...