Return true if there is a cycle in the linked list. Otherwise, return false. 英文版地址 leetcode.com/problems/l 中文版描述 给你一个链表的头节点 head ,判断链表中是否有环。如果链表中有某个节点,可以通过连续跟踪 next 指针再次到达,则链表中存在环。 为了表示给定链表中
Linked List Cycle Given a linked list, determine if it has a cycle in it. Follow up: Can you solve it without using extra space? 方法和原理见1,代码如下: /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), nex...
Given a linked list, return the node where the cycle begins. If there is no cycle, return null. To represent a cycle in the given linked list, we use an integer pos which represents the position (0-indexed) in the linked list where tail connects to. If pos is -1, then there is ...
1. 原始题目 Given a linked list, determine if it has a cycle in it. To represent a cycle in the given linked list, we use an integerposwhich represents the position (0-indexed) in the linked list where tail connects to. Ifposis-1, then there is no cycle in the linked list. Exampl...
Given a linked list, return the node where the cycle begins. If there is no cycle, returnnull. To represent a cycle in the given linked list, we use an integerposwhich represents the position (0-indexed) in the linked list where tail connects to. Ifposis-1, then there is no cycle ...
Note:Do not modify the linked list. Follow up: Can you solve it without using extra space? 给定一个链表,返回链表开始入环的第一个节点。 如果链表无环,则返回null。 说明:不允许修改给定的链表。 进阶:你是否可以不用额外空间解决此题? 代码语言:javascript ...
给定一个链表,判断链表中是否有环。 为了表示给定链表中的环,我们使用整数 pos 来表示链表尾连接到链表中的位置(索引从 0 开始)。 如果 pos 是 -1,则在该链表中没有环。 英文: Given a linked list, determine if it has a cycle in it. To represent a cycle in the given linked list, we use an...
Given a linked list, determine if it has a cycle in it. 给定一个链表,判断它是否有环。 【题目链接】 www.lintcode.com/en/problem/linked-list-cycle/ 【题目解析】 可以使用两个指针,一快一慢,如果有环,则这两个指针一定会相遇。这个方法不需要额外的空间,同时复杂度是O(N)的。符合这道题目的要求...
Explanation: There is a cycle in the linked list, where the tail connects to the 1st node (0-indexed). 分析: 在题设部分已经阐述pos是与本题毫无关系的,所以,主要是围绕链表进行的思考的。 示例代码: public class Solution { public boolean hasCycle(ListNode head) { ...
Returntrueif there is a cycle in the linked list. Otherwise, return false. public class Solution { public boolean hasCycle(ListNode head) { if(head == null) return false; ListNode slow = head; ListNode fast = head.next; while (slow != fast){ ...