Detect cycle in undirected graph: method 1: Union FindThe time complexity of the union-find algorithm is O(ELogV).
int[][] edges = {{0, 1}, {1, 2}, {2, 0}}; boolean result = so.hasCycleDirectedGraph(3, edges); System.out.println(result); } } Detect Cycle in Undirected Graph 无向图找环 Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of n...
Detect cycle in an undirected graph https://www.geeksforgeeks.org/detect-cycle-undirected-graph/ 无向图就简单很多,如果dfs的时候,当前节点的neighbor中有被访问过且不是parent的节点,就一定有环存在。 这里顺便复习一下dfs两种写法:1) dfs最开始判断边界条件 2) dfs前判断边界条件 由于需要dfs时判断是否是p...
Given an undirected graph G = (V, E), does there exist a cycleΓ that visits every node exactly once? 一个有解的图,一个没有 结点 sed 构造方法 计算机 原创 mb61caa1c74a413 2022-01-08 17:24:44 344阅读 sleep(), Sleep() 关于sleep()函数在windows系统和linux系统下是两个不同的...
Given a linked list, determine if it has a cycle in it. Follow up: Can you solve it without using extra space? Solution: solve the problem with one and two steps no cycle case: the faster pointer(two step) reaches the null first ...