If you want to find the current user account using the whoami command, it can be evaluated in the bash script in the following manner: #!/bin/bash # Get the currently logged-in user using whoami current_user=$(whoami) echo "The currently logged-in user is: $current_user" If you deci...
Linux distributions normally display the username of the current user in the Terminal as (Username)@ComputerName. If your Linux distribution doesn't, run "who" or "whoami" in the Terminal to get the username instead. You can use the "w" command to get even more detailed information. If L...
structcompletion*vfork_done;/* for vfork() */ int__user*set_child_tid;/* CLONE_CHILD_SETTID */ int__user*clear_child_tid;/* CLONE_CHILD_CLEARTID */ cputime_tutime,stime,utimescaled,stimescaled; cputime_tgtime; #ifndef CONFIG_VIRT_CPU_ACCOUNTING_NATIVE structcputimeprev_cputime; #en...
第一步是找出当前登陆用户是用user表中的哪一个,用current_user() mysql>selectcurrent_user();+---+|current_user()|+---+|test@192.168.%.%|+---+1rowinset(0.00sec) 第二步用show grants命令,如下: mysql>show grantsfor'test'@'192.168.%.%';+---...
背景:搭建了一套oracle 19c主备库(单实例非CDB,PDB),linux7.5在断电后(没有进行数据库关闭)重启数据库报错如下图,redo当前状态下进行不完全恢复主库后resetlogs 打开主库报错继续报错ORA-00600: internal error code, arguments: [4193], [227], [240], ...
The article presents information about the merits of Canonical's Ubuntu 6.06 LTS (Long-term Support) Linux-based operating system. Ubuntu 6.06 LTS provide improved desktop usability, easy software installation and management fra...
use-after-free in ALSA allowing for a local root compromise by a host user in group "audio" if the vulnerable kernel module is loaded (CVE-2017-15265). Also fixed is an inconsistency in modify_ldt(2)'s memory (de)allocation, which got introduced along with KPTI in our update to -431...
如：gcc gcc-c++ openssl-devel zlib-devel pcre pcre-devel等 先执行cd /usr/local/src/把要下载...
在Linux终端内输入: #ssh 用户名@被访问虚拟机的IP地址或者 ssh 用户名@被访问虚拟机的IP地 putty pem文件登陆 远程登入 ssh putty.exe telnet kubectl进入容器内部 kubelet进程 kubelet是运行在Minion节点上的重要守护进程,是工作在一线的重要工人,它才是负责实例化和启动一个具体Pod的幕后主导,并且掌管着本节点...
ERROR: current user does not have privilege to role su1 --在fs下创建对象,成功 create table fs.tt(id int); CREATE TABLE 【预期输出】: --在su1 下创建对象不报错 create table su1.tt(id int); 【原因分析】: 【日志信息】(请附上日志文件、截图、coredump信息): ...