The input current to the second current source is substantially constant because the process dependent component has been removed by the output current of the first current source. Variable resistors internal to the current source are set ...
Question. A current source drives a current in a coil of resistance R1 for a timet. The same source drives current in another coil of resistance R2for same time. If heat generated is same, find internal resistance of source. d(a) R1R2/R1 + R2(b)R_1+R_2 (c) zero(d)/R_1R^2...
Thank you for this response, unfortunately, my customer is asking for the sense resistor resistance of the current source the drives the LEDs from the AFE. Regards, _renan Up0TrueDown Hello Renan, The LED driver is realized as a current source with high ...
Being that it has very high internal resistance and the load resistance is much lower, current takes the path of least resistance, flowing out of the (high internal resistance) current source and into the load resistance, since it is of much lower resistance. ...
EMF stands for electromotive force, and it is the measure of the energy per unit charge that is supplied by a source, such as a battery. Internal resistance is the resistance within the source that limits the flow of current. EMF and internal resistance are related because as the internal ...
A minus 420 mV anomaly over a sulphide deposit was tested as current source. Two lead electrodes were dug into the ground, one at the place where the negative peak value was found and the other one in a nearby bog. The electrodes were connected through a variable load resistance ranging fr...
Connected to the input stage of the amplifier is a voltage source, VS, and its associated internal resistance, R <S. This could be taken to represent some form of transducer having a low-voltage output in the millivolt range. At the output stage the amplifier acts as a voltage source whe...
The input resistor network can simply source the current to ground; at 65 V, the AD8206, with 200 kohm per input, will have 325 μA flowing to ground.If the current-sense architecture is used, the designer must be concerned with such potential problems. In the case of the first ...
Similarly, assume acurrent sourcewith the value I and internal resistance r. Now according to theOhm’s law, thevoltageacross the source can be calculated as Thus, the voltage across the source, when its terminals are open, is V.
运放的两个输入端都会提供(source)或吸收(sink)电流,我们将运放的内部框图展开,示意如下: 图4 运放内部框图 上图为基于Bipolar工艺制备的运放,Q1和Q2代表反相和同相输入端晶体管,IN与Ip代表了其基极电流(图2中写为IB-和IB+)。 要让Q1和Q2处于线性工作区,基极必须有一定的电流,这种电流就是偏置电流。