for(int i=0;i<pe;i++) if(dis[edge[i].endNode]<(dis[edge[i].startNode]-edge[i].commission)*edge[i].exchangeRate){ dis[edge[i].endNode]=(dis[edge[i].startNode]-edge[i].commission)*edge[i].exchangeRate; sign=true; } if(!sign) break; } if(sign) return false; else retur...
Description Several currency exchange points are working in our city. Let us suppose that each point specializes in two particular currencies and performs exchange operations only with these currencies. There can be several points specializing in the same pair of currencies. Each point has its own e...
POJ-1860 Currency Exchange (最短路) https://vjudge.net/problem/POJ-1860 有多种汇币,汇币之间可以交换,这需要手续费,当你用100A币交换B币时,A到B的汇率是29.75,手续费是0.39,那么你可以得到(100 - 0.39) * 29.75 = 2963.3975 B币。问s币的金额经过交换最终得到的s币金额数能否增加 货币的交换是可以重...
POJ1860-Currency Exchange (正权回路)【Bellman-Ford】,<题目链接><转载于>>>>题目大意:有多种汇币,汇币之间可以交换,这需要手续费,当你用100A币交换B币时,A到B的汇率是29.75,手续费是0.39,那么你可以得到(100-0.39)*29.75=2963.3975B币。问s
题目传送:poj1860 题目描述: Description: Several currency exchange points are working in our city. Let us suppose that each point specializes in two particular currencies and performs exchange operations only with these currencies. There can be several points specializing in the same pair of currencies...
POJ-1860 Currency Exchange (最短路) 2018-06-16 21:00 − https://vjudge.net/problem/POJ-1860 题意 有多种汇币,汇币之间可以交换,这需要手续费,当你用100A币交换B币时,A到B的汇率是29.75,手续费是0.39,那么你可以得到(100 - 0.39) * 29.75 = 2963.3975 B币。问s币的金额经过交换最... lito...
[POJ] [INDEX] [1860] [Currency Exchange][Time: 1000MS] [Memory: 30000K] [难度: 初级] [分类: 最短路径算法] 问题描述有多种汇币,汇币之间可以交换,这需要手续费,当你用100A币交换B币时,A到B的汇率是29.75,手续费是0.39,那么你可以得到(100 - 0.39) * 29.75 = 2963.3975 B币。问s币的金额经过...
Currency Exchange POJ - 1860 题意:币种兑换寻找是否有正环 计算公式 (money - Cost) * Rate 思路:spfa_dfs 判正环 #include<stdio.h>#include<string.h>#include<vector>usingnamespacestd;constintMAX_V=200;structedge{intto;doubleRate,C;};vector<edge>G[MAX_V];boolinstack[MAX_V];doubled[MAX...
poj1860(Currency Exchange) 题目大意: 给你几个国家的货币兑换率,看你是否能通过不同国家的货币兑换之后是自己的财富增加,如增加输出YES,无法增加输出NO。 具体兑换过程: N代表几个国家,M代表几条兑换的信息,S代表起始的国家,V代表你现有的财富金额。 从A兑换到B 得到的财富 :(V-Cab)*Rab 、 测试数据:1 ...
Currency Exchange---poj1860 ( spfa, 回路,最长路) 题目链接: http://poj.org/problem?id=1860 题解: 两种情况YES,一种是存在正权回路; 一种是求最长路后,实现了增值,也是YES; 用spfa来判断是否存在正权回路,其实spfa是可以用来判断是否存在回路的,不管是正权还是负权,只不过它们松弛的条件不同,正权的...