b){ 3 if(a < b) { 4 alert("A is less than B"); 5 } else if(a >...
看到cuda中，有reinterpret_cast<float4*>；这样的操作，和float32是什么关系； 也看到有说“GPU是以四...
float* output) { auto idx = (threadIdx.x + gridIdx.x * blockDim.x) * 4; float4*...
导致用户不得不考虑使用ILP(指令级别的线程内部的前后自我并行, 本优化指南后续章节会说). 而使用了ILP往往会导致使用int4/float4这种向量类型, 而根据已有的资料, 在大Kepler上这样做, 往往会导致严重的寄存器的bank conflict, 同时编译器竭尽全力还无法很好的避免, 这就很尴尬了. 所以手册虽然这里这样说了, 但...
int width = 64, height = 64; float* devPtr; size_t pitch; cudaMallocPitch(&devPtr, &pitch, width * sizeof(float), height); MyKernel<<<100, 512>>>(devPtr, pitch, width, height); // Device code __global__ void MyKernel(float* devPtr, ...
(stop); //计算时间 stop-start float elapsed_time; CHECK(cudaEventElapsedTime(&elapsed_time, start, stop)); printf("start-》stop:Time = %g ms.\n", elapsed_time); CHECK(cudaMemcpy(h_c, d_c, (sizeof(int)*m*k), cudaMemcpyDeviceToHost)); //cudaThreadSynchronize(); //开始stop2 ...
struct cudaChannelFormatDesc { int x, y, z, w; enum cudaChannelFormatKind f; }; where cudaChannelFormatKind is one of cudaChannelFormatKindSigned, cudaChannelFormatKindUnsigned, or cudaChannelFormatKindFloat. cudaMallocMipmappedArray() can allocate the following: A 1D mipmapped array ...
for (int n = 0; n < N; n++) { float psum = 0.0; for (int k = 0; k < K; k++) { psum += a[OFFSET(m, k, K)] * b[OFFSET(k, n, N)]; } c[OFFSET(m, n, N)] = psum; } } } 1. 2. 3. 4. 5.
float* h_B = (float*)malloc(size); // Initialize input vectors ... // Initialize cuInit(0); // Get number of devices supporting CUDA int deviceCount = 0; cuDeviceGetCount(&deviceCount); if (deviceCount == 0) { printf("There is no device supporting CUDA.\n"); ...
float *P = (float*)malloc(sizeof(float)*width); for(int i = 0;i < width;++i){ N[i] = i+1; } M[0] = 3; M[1] = 4; M[2] = 5; M[3] = 4; M[4] = 3; Convolution_1D_basic(N, M, P, mask_width, mask_width/2, width); ...