If 1, ω and ω2 are the cube roots of unity. Then, the value of (1−ω+ω2)(1−ω2+ω4)(1−ω4+ω8)… upto 2n factors is A22n−1 B22n C2n−1 D22n+1Submit Question 2 - Select One If ω is cube root of unity, then ∣∣∣ ∣∣1ωω2ωω21ω21ω∣∣∣ ...
View Solution If 1, ω and ω2 are the cube roots of unity. Then, the value of (1−ω+ω2)(1−ω2+ω4)(1−ω4+ω8)… upto 2n factors is View Solution If ω is cube root of unity, then ∣∣∣ ∣∣1ωω2ωω21ω21ω∣∣∣ ∣∣ is equal to View Solution ...
Squares upto 50 How to Find Cube Root Cube Roots of Unity Perfect Numbers Solved Examples on Perfect Cubes Question 1: Is the number 600 a perfect cube? Let us write down, stating the prime factors of the number 600. \(\begin{array}{l}600 = 2 \times 2\times 2 \times 3 \times 5...
If ω(≠1) is a cube root of unity, then (1−ω+ω2)(1−ω2+ω4)(1−ω4+ω8)…upto 2n is factors, is A 2n B 22n C 0 D 1 Video Solution Text SolutionGenerated By DoubtnutGPT To solve the problem, we need to evaluate the expression: (1−ω+ω2)(1−ω2+ω4)...
To solve the problem, we need to find the value of (1+ω)3−(1+ω2)3, where 1,ω,ω2 are the cube roots of unity. 1. Understanding Cube Roots of Unity: The cube roots of unity are the solutions to the equation z3=1. These roots are: 1,ω=e2πi/3,ω2=e4πi/3 wh...