Step 3: Verify that the equation is balanced Since there are an equal number of atoms of each element on both sides, the equation is balanced. Cu(OH)2 + Na2SO4 + 4NH3 = Cu(NH3)4 + H2O + Na2O + SO4Practice Balancing Cu(OH)2 - + + Na2SO4 -...
不需要复合状态[如(s)(aq)或(g)]。 你可以用小括号()或括号[ ]。 如何平衡方程式 使用本计算器来平衡任何化学方程式或反应!找出发生了哪种反应。 阅读我们的关于如何平衡化学方程式的文章,或在我们的聊天中寻求帮助。例子Al(NO3)3 + H2SO4 + Cu = Al2(SO4)3 ...
一定温度下的难溶电解质AmBn在水溶液中达到溶解平衡时.已知下表数据 物质 Fe2 Fe(OH)3 Ksp/25℃ 8.0×10-16 2.2×10-20 4.0×10-38 完全沉淀时的pH ≥9.6 ≥6.4 3-4 对含等物质的量的CuSO4.FeSO4.Fe2(SO4)3的混合溶液的说法错误的是( ) A
2Na3PO4+3CuSO4=3Na2SO4+ Cu3(PO4)2 ReactantsProducts Na66✔️ P22✔️ O2020✔️ Cu33✔️ S33✔️ Step 3: Verify that the equation is balanced Since there are an equal number of atoms of each element on both sides, the equation is balanced. ...
Compound states [like (s) (aq) or (g)] are not required. You can use parenthesis () or brackets []. How To Balance Equations Balance any equation or reaction using this chemical equation balancer! Find out what type of reaction occured. Read our article on how...
Add 3 molecules of NH3 to the reactant (left-hand) side to balance Hydrogen: Cu(OH)2 + Na2SO4 + 4NH3 = (Cu(NH3)4)SO4 + 2NaOH ReactantsProducts Cu 1 1 ✔️ O 6 6 ✔️ H 14 14 ✔️ Na 2 2 ✔️ S 1 1 ✔️ N 4 4 ✔️...
(Cu(NH3)4)SO4 + 2NaOH = Cu(OH)2 + Na2SO4 + 4NH3 ReactantsProducts Cu 1 1 ✔️ N 4 4 ✔️ H 14 14 ✔️ S 1 1 ✔️ O 6 6 ✔️ Na 2 2 ✔️ Step 3: Verify that the equation is balanced Since there are an equal number ...
4Cu(OH)2+ H2SO4+ Na2S2O5=2Cu2SO4+ Na2SO4+5H2O ReactantsProducts Cu44✔️ O1717✔️ H1010✔️ S33✔️ Na22✔️ Step 3: Verify that the equation is balanced Since there are an equal number of atoms of each element on both sides,...
K2S2O3 1 190.3248 Cu 1 63.546 (NH4)2SO4 4 132.13952 NH3 4 17.03052 To calculate the stoichiometry of K2SO3 + (NH4)2SO3 + (Cu(NH3)4)SO4 = K2S2O3 + Cu + (NH4)2SO4 + NH3 you must balance the equation to find...
H2SO4 + NaOH + Cu(NO3)2 = CuO4S + 2Na(NO3) + H2O ReactantsProducts H 3 2 ❌ S 1 1 ✔️ O 11 11 ✔️ Na 1 2 ❌ Cu 1 1 ✔️ N 2 2 ✔️ Na is not balanced. Add 1 molecule of NaOH to the reactant (left-hand) side to...