Functionalisation of copper (Cu) -based oxide nanostructures has become essential in excitonics industrial device applications that manifest in the conversion and transport of energy such as modern catalytic power generation and flexible or wearable miniaturise electronic products1,2,3,4,5. The exploi...
CU(OH)2+H2SO4=CUSO4+2H2O,CU(OH)2+H2SO4=CUSO4↓+2H2O,这个呢? 扫码下载作业帮搜索答疑一搜即得 答案解析 查看更多优质解析 解答一 举报 Cu(OH)2+H2SO4=CuSO4+2H2O,这个化学方程式对硫酸铜溶于水,不用沉淀符号 解析看不懂?免费查看同类题视频解析查看解答 更多答案(3)...
(2)反应中Cu的化合价从0价升高到-2价,消耗了32g Cu,即32g64g/mol32g64g/mol=0.5mol,则转移电子为1mol,由Cu+2H2SO4(浓)?CuSO4+SO2↑+2H2O可知,还原了0.5mol硫酸,生成0.5mol二氧化硫,即11.2L;故答案为:1;0.5;11.2;(3)氧化还原反应中还原剂的还原性大于还原产物,反应中Cu作还原剂,SO...
Two mixed-valence copper complexes were synthesized with ligands N-(2-pyridylmethyl)acetamide (Hpmac) and N,N'-(2-methyl-2-pyridylpropan-1,3-diyl)bis(acetamide) (H2pp(ac)2). Dimer [Cu2(pmac)2]OTf and trimer [Cu3(pp(ac)2)2].NaOTf both contain fully delocalized, mixed-valence Cu...
故答案为:(1)CaO+H2O=Ca(OH)2(2)Cu+Hg(NO3)2=Hg+Cu(NO3)2(3)CuSO4+Ca(OH)2=CaSO4+Cu(OH)2↓ 点评本题主要考查化学方程式的书写,难度较小. 练习册系列答案 一通百通考必赢系列答案 一线名师夺冠王检测卷系列答案 一线名师提优试卷系列答案 ...
The reaction of a monosubstituted Keggin polyoxometalate (POM) generated in situ with copper–phenanthroline complexes in excess ammonium or rubidium acetate led to the formation of the hybrid metal organic–inorganic compounds A7[Cu2(ac)2(phen)2(H2O)2][Cu3(ac)3(phen)3(H2O)3][Si2W22Cu2O78(...
(2)___NaNO2+___HI=___NaI+___NO↑+___H2O+___I2. 试题答案 在线课程 (1)该反应中元素的化合价变化如下:Cu→Cu(NO3)2,Cu元素的化合价由0价→+2价,一个Cu失去2个电子; HNO3→NO,N元素的化合价由+5价→+2价,一个HNO3得到3个电子,所以得失电子的最小公倍数为6,所以Cu的计量数为3,Cu(NO3)...
于250ml烧杯中加入6.3g CuSO4·5H2O和20ml水,溶完后,边搅拌边加1:1的氨水,直至沉淀完全溶解。加入25ml 3mol/L NaOH 溶液,使Cu(OH)2完全沉淀,抽滤,以温水洗至无SO42–(用BaCl2检验),抽干。(先烧温水200ml,分15次加入。洗到10次以上时再检查。)...
浓硫酸具有强氧化性,它可把不活泼的金属铜氧化.依据化学方程式中 盐酸化合价的变化判断为:铜元素化合价从 0价升高到+2价,被浓硫酸氧化,浓硫酸做氧化剂具有氧化性,根据化学方程式Cu+2H2SO4(浓)═CuSO4+SO2↑+2H2O可知,消耗1molCu,生成1mol二氧化硫气体;故答案为:升高;氧化;氧化;氧化;氧化;1. 浓硫酸具有强氧...
The crystal of [Cu(L-ArgH)2(Ac)2]3H2O was synthesized and its electronic absorption spectrum and photoacoustic spectrum were recorded under room temperature. The spectrums were compared with each other. A semi-empirical method of coordinate-field-theory PLFT was utilized to calculate the ...