std::function是C++11标准库中的一个模板类,用于封装可调用对象(函数、函数指针、成员函数指针、lambda表达式等),并提供统一的调用接口。它的内部实现使用了运算符重载,以实现对不同类型的可调用对象的调用。 std::function的运算符重载主要包括以下几个: 赋值运算符(=):用于将一个std::function对象赋值给另一个std::
function::operator= function::swap function::assign (until C++17) function::operator bool function::operator() function::target_type function::target Non-member functions operator==operator!= (until C++20) swap(std::function) Helper classes uses_allocator<std::function> (until C++17) Deduction ...
function::operator= function::swap function::assign (until C++17) function::operator bool function::operator() function::target_type function::target Non-member functions operator==operator!= (until C++20) swap(std::function) Helper classes uses_allocator<std::function> (until C++17) Deduction ...
Class templatestd::function_refis a non-owning function wrapper.std::function_refobjects can store and invoke reference toCallabletarget- functions,lambda expressions,bind expressions, or other function objects, but not pointers to member functions and pointers to member objects.std::nontypecan be ...
cpp4 std::function std::function<int(int,int)> foo,bar; 用函数类型初始化模板参数
std::function<int(inta)> func_ = std::bind(&MyClass::Func, &my_class, std::placeholders::_1); auto lambda_func_= [&my_class](inta) ->int{returnmy_class.Func(a); } } 2. lambda转成std::function,参考https://www.cnblogs.com/qicosmos/p/4772328.html,做类型萃取,链接还讲了any cla...
cpp4 std::function std::function<int(int,int)>foo,bar; 用函数类型初始化模板参数 本文章为转载内容,我们尊重原作者对文章享有的著作权。如有内容错误或侵权问题,欢迎原作者联系我们进行内容更正或删除文章。
<template class F> class test { public: test(F fn) : fn_(fn) { } private: F fn_; }; 我想指定 F 为std::function,比如说F 可以为std::function<void()>。但是std::function可以有很多种,比如std::function<int()>。我只想限定 F 为std::function,不做进一步具体的限定要怎么写?c++ ...
#include <functional>#include <iostream>usingSomeVoidFunc=std::function<void(int)>;classC{public:C(SomeVoidFunc void_func=nullptr):void_func_(void_func){if(void_func_==nullptr)// specialized compare with nullptrvoid_func_=std::bind(&C::default_func, this, std::placeholders::_1);void_...
member) - (size_t)(&t); 类成员函数的反射 类成员函数指针: typedef std::function<void(Test*)>test_method; method method = &Test::f1; Test *t = new Test(); method(t); uintptr_t ptr = (uintptr_t)& method; (*(test_method*)(ptr))(t) function<void(delctype(this)) ...