*/publicbooleanisCousins(TreeNode root,intx,inty){int[] arr = getTreeDepth(root, x);int[] arr2 = getTreeDepth(root, y);if(arr.length <1|| arr2.length <1) {returnfalse; }returnarr[0] != arr2[0] && arr[1] == arr2[1]; }publicint[] getTreeDepth(TreeNode root,intnum) ...
Binary Tree Level Order Traversal 参考资料: https://leetcode.com/problems/cousins-in-binary-tree/ https://leetcode.com/problems/cousins-in-binary-tree/discuss/238536/My-Easy-Recursive-C%2B%2B-Solution https://leetcode.com/problems/cousins-in-binary-tree/discuss/239376/Java-BFS-time-and-space...
My Solutions to Leetcode problems. All solutions support C++ language, some support Java and Python. Multiple solutions will be given by most problems. Enjoy:) 我的Leetcode解答。所有的问题都支持C++语言,一部分问题支持Java语言。近乎所有问题都会提供多个算
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right (right) {} * }; */ classSolution{ public: TreeNode*replaceValueInTree(TreeNode*root) { ...
0094-Binary-Tree-Inorder-Traversal 0095-Unique-Binary-Search-Trees-II 0096-Unique-Binary-Search-Trees 0098-Validate-Binary-Search-Tree 0099-Recover-Binary-Search-Tree 0100-Same-Tree 0101-Symmetric-Tree 0102-Binary-Tree-Level-Order-Traversal 0103-Binary-Tree-Zigzag-Level-Orde...
在二叉树中,根节点位于深度0处,每个深度为k的节点的子节点位于深度k+1处。 如果二叉树的两个节点深度相同,但父节点不同,则它们是一对堂兄弟节点。 我们给出了具有唯一值的二叉树的根节点root,以及树中两个不同节点的值x和y。 只有与值x和y对应的节点是堂兄弟节点时,才返回true。否则,返回false。
Given the root of a binary tree with unique values and the values of two different nodes of the tree x and y, return true if the nodes corresponding to the values x and y in the tree are cousins, or false otherwise. Two nodes of a binary tree are cousins if they have the same dep...
We are given therootof a binary tree with unique values, and the valuesxandyof two different nodes in the tree. Returntrueif and only if the nodes corresponding to the valuesxandyare cousins. 题目分析及思路 定义二叉树的深度:根结点的深度为0,深度为k的结点的孩子结点的深度为k+1。如果二叉树里...
1 class Solution 2 { 3 public: 4 bool judge(TreeNode* root, int x, int y) 5 { 6 if(root!=NULL) 7 { 8 9 if(root->left&&root->right...
In a binary tree, the root node is at depth0, and children of each depthknode are at depthk+1. Two nodes of a binary tree arecousinsif they have the same depth, but have different parents. We are given therootof a binary tree with unique values, and the valuesxandyof two different...