编程、机器学习和数学 Programming for Everybody (Getting Started with Python) 这个课售后也很好,我至今还能收到一些活动邮件。 Python Basics Machine Learning 机器学习:很硬核但也很基础一门课。吴老师讲得很好,练习作业也很不错,我在Coursera上最喜欢的课程之一! 学习机器学习之前可以顺便学一下线性代数,不然mach...
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Nptel Assignment Answers 2025 756 SubcategoriesNewPopular AI in Human Resource ManagementAI in MarketingAI Knowledge Representation And ReasoningAir Pollution and ControlAn Introduction to Artificial IntelligenceAn Introduction to Programming Through C++Artificial Intelligence Search Methods For Problem SolvingBlock...
综上就是免费注册课程的方法,不过需要注意的是这样注册的课程所有quiz和assignment都是锁定的,其他内容和付费订阅是一模一样的,如果想要做题或者申请证书的话我们可以再申请一个助学金,就可以实现白嫖了～ 阅读全文 age coursera近十年老用户,有问必答关注 是的 不过现在有助学金 扩展阅读: 关于coursera,你所关心...
There are five courses in the specialization each of which includes a hands-on, peer-graded assignment. There is also a capstone project where learners build a data product using real-world data. Following topics are covered in the five courses: Statistical inference Broad theories of inference ...
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However, at compulsory weekly discussions and even final assignment review portals, I came across really low-quality and zero-effort posts. Coursera should find a way to disqualify these users, otherwise they will just taint the credibility of the course and the certificate since peer-review has ...
Q: I cannot submit my assignment?A: This issue should not be happening but if it does please let us know immediately. One temporary work around would be to download your notebook and go to the corresponding programming assignment tab ==> + Create Submission and upload it. ...
There’s also a set of classes where students can be given the same assignment but produce correct but radically different work, or classes where the deliverables are too complex to be judged by software or other students. For example, MIT’s6.033class has severaldesign projectswhose deliverables...
说到底就是因为python不提供对str类型中的list进行赋值的接口,如果你想作类似于list的str[n] = 'sth'的操作会报item assignment not supported的错误。而其他诸如replace()的方法只要不把新指向的引用复制给原引用,原引用及原引用指向的对象都不会改变。 Tuple元组 tuple = (a, b) Lists列表 list = [a, b...