def countInversions(arr): def merge_sort_and_count(arr): if len(arr) <= 1: return arr, 0 mid = len(arr) // 2 left, left_inversions = merge_sort_and_count(arr[:mid]) right, right_inversions = merge_sort_and_count(arr[mid:]) merged, split_inversions = merge_and_count(left, ...
we have an array A and a queries array q f(vector &A, vector<vector> q) q[i][0] = left q[i][1] = right q[i][2] = element for each query, we need to find the number of elements that are greater than or equal to the element given in the query between the range L and ...
'Sort' in exuction plan is showing more than 90 % cost, what to do? 'TRY_CONVERT' is not a recognized built-in function name 'VARCHAR' is not a recognized built-in function name. 'WHEN MATCHED' cannot appear more than once in a 'UPDATE' clause of a MERGE statement. "EXECUTE AT"...
核心就是Merge排序,注意在新建数组的时候直接赋值,append等会导致超时。就是用递归 每次都拿两个排序好的数组 merge排序 ANSWER #!/bin/python3importmathimportosimportrandomimportreimportsys# Complete the countInversions function below.defmerge(arr,left_half,right_half):i,j,k=0,0,0inversions=0left_len...
Solution: importjava.io.*;importjava.util.*;importjava.text.*;importjava.math.*;importjava.util.regex.*;publicclassSolution{publicstaticlongcountInversions(int[]arr){returnmergeSort(arr,0,arr.length-1);}publicstaticlongmergeSort(int[]arr,intstart,intend){if(start==end)return0;longcount=0;in...
No sorting algorithm can sort n elements in better than O(n log n) time if comparing elements. However, there are other ways of sorting elements if we know some information about those elements in advance
Every experiment lasts for 5 min (generating almost 2400 frames), in which a group of 3 people simulate scenarios of a living room where anyone can enter or leave anytime, move in the room as they want and perform any sort of activity they want (e.g., sit, stand, walk or lay down...