Another sorting method, the counting sort, does not require comparison. Instead, you create an integer array whose index range covers the entire range of values in your array to sort. Each time a value occurs in the original array, you increment the counter at that index. At the end, run...
Insertion Sort and the simple version of QuickSort were stable, but the faster in-place version of Quicksort was not (since it scrambled around elements while sorting). In cases where you care about the original order, it is important to use a stable sorting algorithm. In this challenge, y...
shounak647 1 year ago C++ solution. Solving this by merge sort is probably the quickest way, as it is done in O(nlogn) time, as opposed to other methods most of which run in O(n^2). An addition to the merge sort algorithm made specifically for this question is that we need to ke...
Given datasets, print the number of inversions that must be swapped to sort each dataset on a new line. Function Description Complete the function countInversions in the editor below. It must return an integer representing the number of inversions required to sort the array. countInversions has t...
countSort(arr); return 0; } string ltrim(const string &str) { string s(str); s.erase( s.begin(), find_if(s.begin(), s.end(), not1(ptr_fun<int, int>(isspace))) ); return s; } string rtrim(const string &str) { string s(str); s.erase( find_if(s.rbegin(), s.rend(...