Can you solve this real interview question? Count Pairs Of Nodes - You are given an undirected graph defined by an integer n, the number of nodes, and a 2D integer array edges, the edges in the graph, where edges[i] = [ui, vi] indicates that there is an
[LeetCode] 2364. Count Number of Bad Pairs You are given a 0-indexed integer array nums. A pair of indices (i, j) is a bad pair if i < j and j - i != nums[j] - nums[i]. Return the total number of bad pairs in nums. Example 1: Input: nums = [4,1,3,3] Output: 5...
pairs,数对; difference,差; absolute difference,差值的绝对值; absolute difference K,差值的绝对值=K。 题目:Given an integer array nums and an integer k, return the number of pairs (i, j) where i < j such that |nums[i] - nums[j]| == k. The value of |x| is defined as: x if ...
做完这两题再做本题你就会发现我们还是可以对 input 数组排序,排序之后我们用一个 helper 函数分别去找nums[i] + nums[j] <= upper的个数和nums[i] + nums[j] <= lower - 1的个数。 复杂度 时间O(n^2) 空间O(1) 代码 Java实现 classSolution{ publiclongcountFairPairs(int[] nums,intlower,intu...
You are given an arraynumsthat consists of non-negative integers. Let us definerev(x)as the reverse of the non-negative integerx. For example,rev(123) = 321, andrev(120) = 21. A pair of indices(i, j)isniceif it satisfies all of the following conditions: ...
13 changes: 13 additions & 0 deletions 13 2176. Count Equal and Divisible Pairs in an Array Original file line numberDiff line numberDiff line change @@ -0,0 +1,13 @@ 2176. Count Equal and Divisible Pairs in an Arrayhttps://leetcode.com/problems/count-equal-and-divisible-pairs-in-...
0-indexedinteger arraynumsof lengthnand an integerk, returnthenumber of pairs(i, j)such that: 0 <= i < j <= n - 1and nums[i] * nums[j]is divisible byk. Example 1: Input:nums = [1,2,3,4,5], k = 2Output:7Explanation:The 7 pairs of indices whose corresponding products are...
struct Node { int value; int left; int right; int num; int pos; }tree[200005];classSolution{public: int hight; int lower; intfun(int root, int number, int h, int l, int pos){if(pos==-1)returntree[root].num; int b = number & (1<< pos);if(b>0) b=1; ...