leetcode| Count Numbers with Unique Digits Given a non-negative integer n, count all numbers with unique digits, x, where 0 ≤ x < 10n. Example: Given n = 2, return 91. (The answer should be the total numbers in the range of 0 ≤ x < 100, excluding[11,22,33,44,55,66,77,88...
leetcode [357]Count Numbers with Unique Digits Given anon-negativeinteger n, count all numbers with unique digits, x, where 0 ≤ x < 10n. Example: Input:2Output:91Explanation:The answer should be the total numbers in the range of 0 ≤ x < 100, excluding11,22,33,44,55,66,77,88,99...
Can you solve this real interview question? Count Numbers with Unique Digits - Given an integer n, return the count of all numbers with unique digits, x, where 0 <= x < 10n. Example 1: Input: n = 2 Output: 91 Explanation: The answer should be the t
LeetCode 357. Count Numbers with Unique Digits 简介:给定一个非负整数 n,计算各位数字都不同的数字 x 的个数,其中 0 ≤ x < 10n 。 Description Given a non-negative integer n, count all numbers with unique digits, x, where 0 ≤ x < 10n. Example: Input: 2 Output: 91 Explanation: The ...
public int countNumbersWithUniqueDigitsByLoop(int n) { if(n<=1) return (int)Math.pow(10, n); int count=0; for(long i=0;i<Math.pow(10, n);i++) { char[] array=(""+i).toCharArray(); Set<Character> set=new HashSet<>(); ...
classSolution {public:intcountNumbersWithUniqueDigits(intn) {if(n ==0)return1;intres =0;for(inti =1; i <= n; ++i) {res+=count(i); }returnres; }intcount(intk) {if(k <1)return0;if(k ==1)return10;intres =1;for(inti =9; i >= (11- k); --i) { ...
357. Count Numbers with Unique Digits 题目 Given anon-negativeinteger n, count all numbers with unique digits, x, where 0 ≤ x < 10n. Example: Input: 2 Output: 91 Explanation: The answer should be the total numbers in the range of 0 ≤ x < 100,...
[LeetCode] Count Numbers with Unique Digits 计算各位不相同的数字个数 Given a non-negative integer n, count all numbers with unique digits, x, where 0 ≤ x < 10n. Example: Given n = 2, return 91. (The answer should be the total numbers in the range of 0 ≤ x < 100, excluding ...
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Given a non-negative integer n, count all numbers with unique digits, x, where 0 ≤ x < 10^n. Example: Given n = 2, return 91. (The answer should be the total numbers in the range of 0 ≤ x < 100, excluding [11,22,33,44,55,66,77,88,99]) ...