来自专栏 · LeetCode刷题记录 1534. Count Good Triplets 难度:e BF跟谁讲理…… class Solution: def countGoodTriplets(self, arr: List[int], a: int, b: int, c: int) -> int: res = 0 n = len(arr) for i in range(n-2): for j in
Can you solve this real interview question? Count Good Triplets - Given an array of integers arr, and three integers a, b and c. You need to find the number of good triplets. A triplet (arr[i], arr[j], arr[k]) is good if the following conditions are tru
【leetcode】1534. Count Good Triplets 题目如下: Given an array of integersarr, and three integersa,bandc. You need to find the number of good triplets. A triplet(arr[i], arr[j], arr[k])is good if the following conditions are true: 0 <= i < j < k < arr.length |arr[i] - ...
package LeetCode_1534 /** * 1534. Count Good Triplets * https://leetcode.com/problems/count-good-triplets/ * * Given an array of integers arr, and three integers a, b and c. You need to find the number of good triplets. A triplet (arr[i], arr[j], arr[k]) is good if the ...
packageleetcodefunccountTriplets(arr[]int)int{prefix,num,count,total:=make([]int,len(arr)),0,0,0fori,v:=rangearr{num^=v prefix[i]=num}fori:=0;i<len(prefix)-1;i++{fork:=i+1;k<len(prefix);k++{total=prefix[k]ifi>0{total^=prefix[i-1]}iftotal==0{count+...
Can you solve this real interview question? Count Square Sum Triples - A square triple (a,b,c) is a triple where a, b, and c are integers and a2 + b2 = c2. Given an integer n, return the number of square triples such that 1 <= a, b, c <= n. Example
1656-count-good-triplets.cpp README.md count-good-triplets.cpp 1669-minimum-cost-to-cut-a-stick 169-majority-element 17-letter-combinations-of-a-phone-number 1721-maximum-profit-of-operating-a-centennial-wheel 173-binary-search-tree-iterator 1744-number-of-ways-to-form-a-target-string-given-...
leetcode_easy_array problem 1534. Count Good Triplets solution #1: Brute Force code solution #2: optimational Brute Force; code: solution #3: code 参考 1.leetcode_1534. Count Good Triplets; 完 各美其美,美美与共,不和他人作比较,不对他人有期待,不批判他人,不钻牛角尖。
链接:https://leetcode-cn.com/problems/count-triplets-that-can-form-two-arrays-of-equal-xor 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 思路是位运算。既然 a 和 b 都是位运算的结果,而且a == b所以根据XOR的性质我们可以得出 a ^ b = 0 的结论,因为两数相同异或为0,这...
nums[i] * nums[j]能被k整除。 示例1: 输入:nums = [1,2,3,4,5], k = 2输出:7解释:共有 7 对下标的对应积可以被 2 整除: (0, 1)、(0, 3)、(1, 2)、(1, 3)、(1, 4)、(2, 3) 和 (3, 4) 它们的积分别是 2、4、6、8、10、12 和 20 。