import java.util.Scanner; class Home04_08{ public static int count(String a, char b) { int count = 0; for (int i = 0;i
publicclassCountExample{publicstaticvoidmain(String[]args){Stringstr="Hello, world!";charc='o';intcount=countOccurrences(str,c);System.out.println("The count of '"+c+"' in '"+str+"' is: "+count);}publicstaticintcountOccurrences(Stringstr,charc){char[]charArray=str.toCharArray();intco...
Some developers may prefer to use core Java. There are many ways for counting the number of occurrences of a char in a String. Let’s start with a simple/naive approach: StringsomeString="elephant";charsomeChar='e';intcount=0;for(inti=0; i < someString.length(); i++) {if(someStr...
*/publicclassStringCount {publicstaticvoidmain(String[] args) { Scanner sc=newScanner(System.in); System.out.println("请输入一个字符串:"); String input=sc.next();intcountUpper = 0;//大写字母intcountLower = 0;//小写字母intcountNumber = 0;//数字intcountOther = 0;//其他字符char[] cha...
JAVA代码:由于在JAVA的API中没有count的,所以直接写了返回值为int类型的count类,不过没有超时,合格的。 importjava.util.Scanner;publicclassMain {publicstaticintcount(charc,String string) {intnum = 0;for(inti = 0;i < string.length();i++) {if(c ==string.charAt(i)) { ...
fnunique_letter_string(s:&str)->i32{// key : 某一种字符// value : 出现这种字符依次的位置letmutindies:HashMap<char,Vec<i32>>=HashMap::new();for(i, c)in s.chars().enumerate(){ indies.entry(c).or_insert_with(Vec::new).push(i asi32);}letmutres=;for(_, arr)in indies.it...
the index to the firstcharof the text range. endIndex Int32 the index after the lastcharof the text range. Returns Int32 the number of Unicode code points in the specified text range Attributes RegisterAttribute Exceptions IndexOutOfBoundsException ...
In Reference Feedback Definition Namespace: Java.Lang Assembly: Mono.Android.dll Determines the number ofcharvalues needed to represent the specified character (Unicode code point). C# [Android.Runtime.Register("charCount","(I)I","")]publicstaticintCharCount(intcodePoint); ...
Stringinput="howtodoinjava.com".toLowerCase();Map<String,Long>counts=input.chars().mapToObj(c->(char)c)// Filter characters to include only vowels and consonants.filter(c->"aeiou".indexOf(c)!=-1||"bcdfghjklmnpqrstvwxyz".indexOf(c)!=-1)// Collect the filtered characters into a ma...
fn unique_letter_string(s: &str) -> i32 { // key : 某一种字符 // value : 出现这种字符依次的位置 let mut indies: HashMap<char, Vec<i32>> = HashMap::new(); for (i, c) in s.chars().enumerate() { indies.entry(c).or_insert_with(Vec::new).push(i as i32); ...