那么我们来分析题目中的第一个例子00110011,符合要求的子字符串要求0和1同时出现,那么当第一个1出现的时候,前面由于前面有两个0,所以肯定能组成01,再遇到下一个1时,此时1有2个,0有2个,能组成0011,下一个遇到0时,此时0的个数重置为1,而1的个数有两个,所以一定有10,同理,下一个还为0,就会有1100存在,...
leetcode@ [327] Count of Range Sum (Binary Search) https://leetcode.com/problems/count-of-range-sum/ Given an integer arraynums, return the number of range sums that lie in[lower, upper]inclusive. Range sumS(i, j)is defined as the sum of the elements innumsbetween indicesiandj(i≤j...
packageleetcodeimport("sort""github.com/halfrost/leetcode-go/template")// 解法一 线段树funccountSmaller(nums[]int)[]int{iflen(nums)==0{return[]int{}}st,minNum,numsMap,numsArray,res:=template.SegmentCountTree{},0,make(map[int]int,0),[]int{},make([]int,len(nums))fori:=0;i<len...
swill only consist of "0" or "1" characters. 解法1: 使用两个计数器,记录连续1和0的次数。每次循环时候,如果当前数字的计数器比之前数字的计数器数值小,则ans+=1。 计数细节:看到计数连续出现的字符,当s[i]==s[i-1],计数器+=1,否则reset计数器,将上次的计数存起来。 class Solution(object): def ...
LeetCode 696. Count Binary Substrings 原题链接在这里:https://leetcode.com/problems/count-binary-substrings/description/ 题目: Give a strings, count the number of non-empty (contiguous) substrings that have the same number of 0's and 1's, and all the 0's and all the 1's in these ...
[leetcode] 401. Binary Watch Description A binary watch has 4 LEDs on the top which represent the hours (0-11), and the 6 LEDs on the bottom represent the minutes (0-59). Each LED represents a zero or one, with the least signific......
LeetCode 0236 - Lowest Common Ancestor of a Binary Tree node.js数据分析 Given a binary tree, find the lowest common ancestor (LCA) of two given nodes in the tree. Reck Zhang 2021/08/11 1720 DFS基础问题-LeetCode 98、101(二叉树中序遍历,层次遍历) ...
package leetcode import ( "sort" "github.com/halfrost/leetcode-go/template" ) // 解法一 线段树,时间复杂度 O(n log n) func countRangeSum(nums []int, lower int, upper int) int { if len(nums) == 0 { return 0 } st, prefixSum, sumMap, sumArray, res := template.SegmentCountTree...
class Solution(object): def countBinarySubstrings(self, s): """ :type s: str :rtype: int """ N = len(s) res = 0 for i in range(N): c1, c0 = 0, 0 if s[i] == "1": c1 = 1 else: c0 = 1 for j in range(i + 1, N): if s[j] == "1": c1 += 1 else: ...
LeetCode 696. Count Binary Substrings 原题链接在这里:https://leetcode.com/problems/count-binary-substrings/description/ 题目: Give a strings, count the number of non-empty (contiguous) substrings that have the same number of 0's and 1's, and all the 0's and all the 1's in these ...