View Solution ∫cos2xequals(A)tanx+cotx+C(B)tanx−cotx+C(C)tanxcotx+C(D)tanx−cot2x+C View Solution Exams IIT JEE NEET UP Board Bihar Board CBSE Free Textbook Solutions KC Sinha Solutions for Maths Cengage Solutions for Maths
Prove that : cotxcot2x+cot2xcot3x+2=cotx(cotx−cot3x) View Solution Show that cotθ⋅cot2θ+cot2θ⋅cot3θ+2=cotθ(cotθ−cot3θ) View Solution Prove that cotxcot2x−cot2xcot3x−cot3xcotx=1 View Solution Let α and β be two real roots of the equation 5cot2x−3cotx...
根据三角函数的基本关系csc2x=1+cot2x,可得cot2x=csc2x−1。 那么∫cot2xdx=∫(csc2x−1)dx。 然后根据积分的性质∫(f(x)−g(x))dx=∫f(x)dx−∫g(x)dx进行计算: ∫(csc2x−1)dx=∫csc2xdx−∫1dx。 根据常见积分公式,∫csc2xdx=−cotx+C1(C1为常数)。 对于∫1dx,因为x的导数...
cot2x/cotx =tanx/tan2x =sinx/cosx * cos2x/sin2x =sinx/cosx * cos2x/(2sinxcosx)=cos2x/(2cos²x)当x-->0时，原式=1/2
微积分limlim cotx/cot(2x)x趋向于0求lim值((x+1)√(5x))/2x^2 求导 答案 第一个用 无穷小量等价 tanx=x=sinx 当x趋于0时即tanx/x=1=tan2x/tanx=2*x*tan(2x)/2x*tanx=2*(tan2x/2x)*(x/tanx)=2*1*1=2第二个=√(5x)+(x+1)√(5/x)-((x+1)√(5x)4x)/4x^4相关...
cot2x/cotx =tanx/tan2x =sinx/cosx * cos2x/sin2x =sinx/cosx * cos2x/(2sinxcosx)=cos2x/(2cos²x)当x-->0时,原式=1/2
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=cos2x/(2cos²x)当x-->0时,原式=1/2结果一 题目 lim x——0的正无穷大(cot2x/cotx) 答案 cot2x/cotx=tanx/tan2x=sinx/cosx * cos2x/sin2x=sinx/cosx * cos2x/(2sinxcosx)=cos2x/(2cos²x)当x-->0时,原式=1/2相关推荐 1lim x——0的正无穷大(cot2x/cotx) ...
f(tanx)=cot2x=(1-tanx*tanx)/(2tanx)f(x)=(1-x∧2）/（2X）所以f(cotx)=(1-cotx*cotx)/(2cotx)=-(1-tanx*tanx)/(2tanx)=-cot2x
解析 csc2x+cot2x=1/(sin2x)+(cos2x)/(sin2x) =(1+cos2x)/sin2x =[1-(sinx)^2+(cosx)^2]/(2sinx*cosx) =[2(cosx)^2]/(2sinx*cosx) =cosx/sinx =cotx 分析总结。 cot2x化简为cotx求过程扫码下载作业帮拍照答疑一拍即得答案解析查看更多优质解析举报csc2x...