sin(PI+a) = -sinacos(PI-a) = -cosa所以sin(PI+a)cos(PI-a)=sinacosa=1/2*sin(2a)= tana/(1+(tana)^2) = -3/10 解析看不懂?免费查看同类题视频解析查看解答 相似问题 tana=2求sin(pi-a)cos(2pi-a)sin(-a+3pi/2)/tan(-a-pi)sin(-pi-a) tanA=a,则sin(-5π-A)cos(3π+...
3 = - \cos a\$ \$\cos ( \pi - a ) = 2 \sqrt 2 / 3 = - \cos a\$ \$\cos a = - 2 \sqrt 2 / 3\$ a在第三象限 \$\sin a = - 1 / 3\$ \$\cos ^ { 2 } ( \pi / 4 - a / 2 ) + \sin ( 3 \pi + a / 2 ) \sin ( 3 \pi / 2 ...
分子/分母=-sin²a/-sina=sina
a属于(0,pi/2),sina=3/5,则根号2*cos(a+pi/4)等于? 已知cos(a-派/6)+sina=4/5根号3,则sin(a+7/6派)的值是? 已知cos(a-π/6)+sina=(4*根号3)/5,则sin(a+7π/6)的值是( ) 特别推荐 热点考点 2022年高考真题试卷汇总 2022年高中期中试卷汇总 2022年高中期末试卷汇总 2022年高中月考...
tana=tan(π+a)=3cos(π-a)=-cosasin(π+a)=-sinacos(-a)=cosasin(2π+a)=sina(2cos(π-a)-3sin(π+a))/(4cos(-a)+sin(2π+a))=(-2cosa+3sina)/(4cosa+2sina)上下同时除以cosa=(-2+3tana)/(4+2tana)=(-2+3×3)/(4+2...
4.如果A为锐角,$$ \sin ( \pi + A ) = - \frac { 1 } { 2 } $$,那么$$ \cos ( \pi - A ) $$等于 ( ) A.-$$ \frac { 1 } { 2 } $$ B.$$ \frac { 1 } { 2 } $$ C.-$$ \frac { \sqrt { 3 } } { 2 } $$ D.$$ \frac { \sqrt { 3 } } ...
化简: \$\sin ( 2 \pi + a ) \cos ( \pi - a ) \cos \left( \frac { \pi } { 2 } - a \right) \cos \left( \frac { 7 \pi } { 2 } - a \right)\$ \$\cos ( \pi - a ) \sin ( 3 \pi - a ) \sin ( - \pi + a ) \sin \left( \frac { 5...
Development of a Core Outcome Set for users and funders of lower-limb prosthetic interventions (PI-COS): a step to inform the benefits measured in prosthetic health economic evaluationsView further author informationhttps://orcid.org/0000-0003-3614-7787...
If A=int_(0)^( pi)(cos x)/((x+2)^(2))dx, then int_(0)^( pi/2)(sin2x)/(x+1)dx is equal to View Solution The value of int_(-pi)^(pi)(cos^(2)x)/(1+a^(2))dx,a gt 0 , is View Solution Ifa>0, then the value of∫π−πcos2x1+axdxis equal to - ...
समाकल int(-pi)^(pi) (cos^(2) x)/(1+a^x)dx का मान है जहां a gt 0