cos2x−sin2x=1+tanx1−tanx. 相关知识点: 试题来源: 解析 证明见解析. 右边=1+sinxcosx1−sinxsinx=cosx+sinxcosx−sinx =(cosx+sinx)2(cosx−sinx)(cosx+sinx) =cos2x+sin2x+2sinxcosxcos2x−sin2x =1+2sinxcosxcos2x−sin2x=左边. 左边=sin2x+cos2x+2sinxcosxcos2x−sin2x =(cosx...
解:利用辅助角公式: a sina+bosd=5a4sin(+4) 1原式= √2((√2)/2sin2x+(√2)/2cos2x)=√2(sin2x10)(T1)/y+tos7*sinπ/(4) =√2sin(2x+π/(4)) 故其周期(w为x数) T=(2π)/(|w|)=(2π)/2=π (2)同理,原式=2((ax+sinx)=2(sin()x+inx) =2sin(x+π/(3)) 故...
化简(1+cos2x/sin2x)乘以(1+cosx/cosx) 原式=(2cos²x)/(2sinxcosx)*(1+cosx)/cox=(1+cosx)/sinx=2cos²(x/2)/(2sinx/2cosx/2)=cos(x/2)/sin(x/2)=cot(x/2) 26546 化简(sin2x)/(1+cos2x)*(cosx)/(1+cosx) cos2x=cosx*cosx-sinx*sinx=1-2*sinx*sinx;sin2x=2*sinx*cosx;...
\[ \lim_{x \to 0} \frac{1 - \cos 2x}{x \sin 2x} \]利用等价无穷小的性质，我们知道 \[ 1 - \cos 2x \sim \frac{(2x)^2}{2} = 2x^2 \]同时 \[ \sin 2x \sim 2x \]将上述等价无穷小代入原极限表达式中，我们得到 \[ \lim_{x \to 0} \frac{2x^2}{x \cdot 2...
Answer to: Find the slope of the tangent to y = sin2x + cos2x at the point where x = pi. a) 0.112 b) 0 c) 1 d) -3.124 By signing up, you'll get...
百度试题 结果1 题目0380(2)lim_(x-10)⋅x⋅cost2x 解:力05林=lim_(x→0)x⋅(cos2x)/(sin2x) =lim_(x→0)x/(2x)-cos2x =1/20K-Ex) 相关知识点: 试题来源: 解析解limx⋅tot2λl = =lim_(x→0)x/(2x) =1/2 反馈 收藏 ...
(4),π/(2)) 上单调递增,A正确; 作出 y=|sin2x|cos|x| 的图象如图47(3)所示,由图象知其周期 为π/(2) ,在区间 (π/(4),π/(2)) 上单调递减,排除B.] A了 1 y=sin lxl -2 3 0 2-1 (1) y=lcos 2xl TT TO T 4 1ī -1 2 A了 1F y=lsin 2xl - 一T -音 等...
दिया गया समीकरण cos4x=cos2x :. 4x=2npipm2x,n in Z rArr 4xpm2,=2npi,n in Z rArr{{:(2x=2npi",",n in Z),(6x=2npi",",n in Z):} अतः अभीष्ट हल है x=n pi, n in Z या x=(n
Answer Step by step video, text & image solution for फलन f(x)=cos2x-sin2x के परिसर में समुच्चय है by Maths experts to help you in doubts & scoring excellent marks in Class 12 exams.Updated on:21/07/2023Class...
$$sinx \sim x (x \to 0)$$ 那么,当x趋于0时,sinx²与x²也是等价无穷小: $$sin²x \sim x² (x \to 0)$$ 最后一步:替换 现在,我们已经得到了所有需要的等式: 1-cos2x = 2sin²x sin²x ~ x² (x趋于0) 将第二条等式代入第一条等式,便得到: $$1-cos2x \sim 2x² ...