sin(2x)=2sinxcosxandcos(2x)=cos2x−sin2x. Answer and Explanation: Given Data: sinx −13 The anglexis in third quadrant. If we have a right... Learn more about this topic: Trigonometric Functions | Definition, Formula & Examples ...
Rewrite the expression in terms of the functions {eq}\cos x {/eq} and {eq}\sin x {/eq}. {eq}\csc x+\tan^2x\csc x {/eq} (a) {eq}\frac{1}{\sin x\cos x} {/eq} (b) {eq}\frac{\sin x...
We can use the cosine addition formula to combine the terms. The formula states:cosA+cosB=2cos(A+B2)cos(A−B2)In our case, let A=3x and B=x:cos3x+cosx=2cos(3x+x2)cos(3x−x2)=2cos(2x)cos(x)Thus, we can rewrite the equation as:2cos(2x)cos(x)−cos(2x)=0 Step 2:...
Step 5: Substitute for sinxsin3xUsing the product-to-sum formula again for sinxsin3x:sinxsin3x=12(cos(2x)−cos(4x))Now we can substitute this back:12∫(1−cos(6x)2−12(cos(2x)−cos(4x)))dx Step 6: Combine and IntegrateCombining the terms gives:14∫(1−cos(6x)−cos...
Answer to: Determine what is u and dv. \displaystyle \int e^{-x} \cos 2x \ dx By signing up, you'll get thousands of step-by-step solutions to your...
Evaluate f_x and f_y at the indicated point. f (x, y) = arccos (x y) Point (1, 1) How to solve cos(2x) - cos(x) = 0 If c o s x = 5 13 and x is in QI, find the exact value of sin2x, cos2x and tan2x. Also state the quadrant in which the angle 2x ...
The double-angle formulas can actually be expressed in terms of the tangent function instead of the commonly used sine and cosine functions. The double-angle formula of the sine function in terms of the tangent function is: sin2x=2tanx1+tan2x ...
Please direct questions about technical support or the Study.com website to customer support. Drop photo or image here to upload or select file Get Answer By submitting, I am agreeing to the Terms of Use and Honor Code. Already a member? Log in here ...
NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year pap...
∫sinx+cosx9+16sin2xdx, we will follow a systematic approach. Step 1: Substitute for sinx+cosx Let t=sinx−cosx. Then, differentiating both sides with respect to x: dt=cosxdx+sinxdx=(cosx+sinx)dx. This implies: dx=dtcosx+sinx. Step 2: Express sinx+cosx in terms of t We can ...