sin410°cos145°+sin680°sin(-35°)=sin50°(-cos35°)+sin(-40°)sin(-35°)=-sin50°cos35°+sin40°sin35°=-sin50°cos35°+cos50°sin35°=sin(35°-50°)=-sin15°=-sin(45°-30°)=-(sin45°cos30°-cos45°sin30°)-( 2 2• 3 2- 2 2• 1 2)= 2- 6 4,故答案...