Answer to: Prove the identity. sin theta cot theta = cos theta. By signing up, you'll get thousands of step-by-step solutions to your homework...
Answer to: Establish the given identity: sec theta - cos theta = sin theta tan theta By signing up, you'll get thousands of step-by-step solutions...
( (1+(sin)(θ )+(cos)(θ ))/(1+(sin)(θ )-(cos)(θ ))=(1+(cos)(θ ))/((sin)(θ ))) 相关知识点: 试题来源: 解析 The provided equation is an identity but there are no steps available. ( (1+(sin)(θ )+(cos)(θ ))/(1+(sin)(θ )-(cos)(θ ))=(1+(cos)(...
sin^(2)theta+cos^(2)theta=1 Squaring both sides sin^(4)theta+cos^(4)theta =1-2 sin^(2)theta.cos^(2)theta Put theta= 90^(@) =1-2sin^(2)90^(@).cos^(2)90^(@)=1-0=1
To prove the trigonometric identity T3−T5T1=T5−T7T3 where Tn=sinnθ+cosnθ, we will start by substituting the values of Tn for n=1,3,5,7. Step 1: Substitute the values of Tn - T1=sinθ+cosθ- T3=sin3θ+cos3θ- T5=sin5θ+cos5θ- T7=sin7θ+cos7θ Step 2: Expre...
Identify the Polar Equation r=1/(cos(theta)+5sin(theta))( r=1/((cos)(θ )+5(sin)(θ )))
化简sin(theta)*cos(theta)*csc(theta)sin(θ)⋅cos(θ)⋅csc(θ)sin(θ)⋅cos(θ)⋅csc(θ) 将csc(θ)csc(θ) 重写为正弦和余弦形式。 sin(θ)cos(θ)⋅1sin(θ)sin(θ)cos(θ)⋅1sin(θ)约去sin(θ)sin(θ) 的公因数。 点击获取更多步骤... cos(θ)cos(θ)...
即Z^n=\cos n\theta +i\sin n\theta 数学归纳法的证明步骤: 第一步:验证n取第一个自然数时成立 第二步:假设n=k时成立, 然后以验证的条件和假设的条件作为论证的依据进行推导, 在接下来的推导过程中不能直接将n=k+1代入假设的原式中去。 最后一步总结表述。 本题中还用到了以下公式: \cos (...
The trigonometric angle identity sin(α+β)=sinαcosβ+cosαsinβsin(α+β)=sinαcosβ+cosαsinβ is exactly what you need. Note that A2+B2=C2A2+B2=C2, or (A/C)2+(B/C)2=1.(A/C)2+(B/C)2=1. Thus there exists an angle ϕϕ such that c...
Establish the identity. {eq}\displaystyle\dfrac {\sin \theta - \cos \theta} {\cos \theta} + \dfrac {\sin \theta + \cos \theta} {\sin \theta} = \csc \theta \sec \theta {/eq} Establishing Trigonometric Identity Trigonometric identity ...