Find the exact solutions of the equation in the interval {eq}[0, 2 \pi) {/eq}. {eq}\sin 2x + \cos x = 0 {/eq} Trig Equations: We often find ourselves in a situation where we must solve an equation that involves different trigonometric functions. ...
Page 11: 相关知识点: 试题来源: 解析 x为任意实数 方程sin²(x) + cos²(x) = 1 是三角函数的毕达哥拉斯恒等式,适用于所有实数x。无论x的具体值是什么,该等式始终成立,因此解集为全体实数。题目本身完整且无需额外条件。反馈 收藏
Find the solution of the equation ( sin x + cos x ) sin 2 x =a(sin^(3) x + cos^(3) x) located between (pi)/(2) and pi and for which values of 'a' does this
cos2x+sinx=1 x = ___ Question: Find all solutions in the interval[0,2π] cos2x+sinx=1 x = ___ Solution of Trigonometry Equation: Firstly simplify the given trigonometry equation to get the equation with only one variable. After ...
sinx+cosx=cos2x1−sin2x View Solution Solve sin2x-cos2x=sinx-cosx View Solution Solve for x:sin2x+sinx+cos2x+cosx+1=0 View Solution Answer the equation: ∫sinx+sin2xcos2x+cosxdx View Solution সমাধান করো:cosx+sinx=cos2x+sin2x ...
cos x cos2x-2sin xsin 2xEquate derivative to zero and use double angle formulaeRemove factor of cos x and reduce equation to one in a single trig functionObtain 6sin² x = 1, 6cos² x = 5 or 5tan²x = 1Solve and obtain x=0.421[Alternative : Use double angle formula M1....
【解析】 METHOD1 $$ \frac { \Delta y } { d x } = - \sin x + \cos x \\ M \\ y \frac { \sqrt { 1 1 } } { 4 x } = ( \cos x + \sin x ) ( - \sin x + \cos x ) \\ A1 \\ = \cos ^ { 2 } x - \sin ^ { 2 } x \\ AG \\ = \cos 2 x $$ ...
Find an equation of the tangent line to y = sin(x^2) - cos^2(x) at the point (0, -1). Find the equation of the tangent line to the curve y = 5 x cos x at the point (pi, -5 pi). Find an equation for the tangent line to g(x) ...
解 sina=cos2a即 sina=1-2（sina）^2，令t=sina，则t∈[-1,1]t=1-2t^2，即 2t^2+t-1=0 （2t-1）（t+1）=0 解得t=1/2或t=-1，满足t∈[-1,1]综上sina=1/2或sina=-1，即 a=π/6或a=-π/2 （一个周期内 多个周期还有其他解）
Answer to: Verify the following equation is a trigonometric identity. (\sin x + \cos x)^{2} = 1+ sin(2x) By signing up, you'll get thousands of...