To solve the problem, we need to find the value of bcos2θ+asin2θ given that tanθ=ab. 1. Use the given information: We know that tanθ=ab. 2. Express cos2θ and sin2θ in terms of tanθ: - The identities for cos2θ and sin2θ in terms of tanθ are: cos2θ=1−tan...
Answer to: Write the following in terms of sin theta and cos theta, then simplify if possible. \frac{\tan\theta}{\cot\theta} By signing up, you'll...
sin2(θ)+cos2(θ)=1 由于 ( \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} )，我们可以将上述恒等式转换为涉及tan的形式：1+tan2(θ)=cos2(θ)1 因此，如果我们知道了tan的值，我们可以通过以下公式计算cos的值：cos(θ)=1+tan2(θ)1 同样，如果我们知道了cos的值，我们可以计算tan的...
Step by step video & image solution for tan^(2) theta - 1 / cos^(2) theta =-1 అని చూపండి. by Maths experts to help you in doubts & scoring excellent marks in Class 10 exams. Updated on:21/07/2023 ...
Formula for cos 2 theta The formula for the cosine of a double angle is a trigonometric identity allowing us to quickly determine the value of the cosine of an angle if we know the cosine or sine value of half of the angle. The cos 2 theta, or, to write it in a more beautiful way...
Answer to: Find the exact value of sin theta and tan theta when cos theta has the indicated value. cos theta = 2 / 5 By signing up, you'll get...
百度试题 结果1 题目已知\( \tan \theta = 2 \),则\( \sin \theta \cos \theta \)的值为___。相关知识点: 试题来源: 解析 \( \frac{2}{5} \) 反馈 收藏
,∴ (sin θ )(cos θ )=tan θ =2,∴ tan 2θ =(2tan θ )(1-tan ^2θ )=(2* 2)(1-2^2)=-43.故答案为:-43. 相关推荐 1已知,则的值为___. 22.(★★☆)已知 sinθ=2cosθ ,则(sin(m/2+n)⋅nc(cosn))/(n(π/(2)-n)⋅n(π-n)) A.2B.-2C.02/3 3已知,则...
∵tan\theta =2=\frac{sin\theta }{cos\theta } ∴sin\theta =2cos\theta tan^2\theta =\frac{1-cos^2\theta }{cos^2\theta }=\frac{1}{cos^2\theta }-1=4 ∴cos^2\theta =\frac{1}{tan^2\theta +1}=\frac{1}{5} ∴1+sin\theta cos\theta =1+2cos^2\theta =1+\frac{2}...
(1)因为角theta 的终边经过点P(m,2sqrt2m)(m>0),所以r=sqrt((m^2)+8(m^2))=3m,所以sinθ=frac((2sqrt2m))((3m))=frac((2sqrt2))3,cosθ=fracm((3m))=frac13,tanθ=frac((2sqrt2m))m=2sqrt2;(2)因为f(θ)=frac(((-sinθ)sinθsinθtanθ))((cosθcosθ(-cosθ)))=(tan^...