यदि -pi le x le pi, , - pi le y le pi तथा cos x + cos y = 2 हो ,तो cos (x - y) का मान है
The required Taylor Series is: f(x)=−1 Explanation: The Taylor Series of f(x) about the pivot x=a is ... What is the value of cos(2π+x) if sinx=0.3 ? https://socratic.org/questions/what-is-the-value-of-cos-2pi-x-if-sin-x-0-3 ±0.95 Explanation: cos(x+2π)=cosx...
cos(π2−x)cos(π2-x) 使用两角差的公式cos(x−y)=cos(x)cos(y)+sin(x)sin(y)cos(x-y)=cos(x)cos(y)+sin(x)sin(y)。 cos(π2)cos(x)+sin(π2)sin(x)cos(π2)cos(x)+sin(π2)sin(x) 化简项。 点击获取更多步骤... ...
यदि f(x)=cos[(pi)/(x)]cos{(pi)/(2)(x-1)}, (जहाँ [*] महत्तम पूर्णांक फलन है ) हो, तो f(x) सतत है
解: \dfrac {\sin (-x)\cos (π-x)}{\sin (\pi +x)\cos (2\pi -x)}- \dfrac {\sin (π-x)\cos (π+x)}{\cos ( \dfrac {π}{2}-x)\cos (-x)} = \dfrac {(-\sin x)(-\cos x)}{(-\sin x)\cos x}- \dfrac {\sin x(-\cos x)}{\sin x\cos x}=-...
解答：f(x)=cos(2pi-x)-x^3sin1/2x =cosx-x^3*sin(1/2x)∴ f(-x)=cos(-x)-(-x)^3*sin(-1/2x)=cosx-(-x^3)*[-sin(1/2x)]=cosx-x^3*sin(1/2x)=f(x)∴ f(x)是偶函数。
cos(-x) = cosxcos (π - x) = - cosx所以cos(-x) + cos(π-x) = cosx - cosx = 0cos(π+x) = -cosx所以cos(π+x) + cosx = -cosx + cosx = 0所以cos(-x) + cos(π-x) = cos(π+x) + cosx
求振幅、周期和相移 cos(x-pi) 使用acos(bx−c)+dacos(bx-c)+d的形式求用于求振幅、周期、相移和垂直位移的变量。 a=1a=1 b=1b=1 c=πc=π d=0d=0 求振幅|a||a|。 振幅:11 求cos(x−π)cos(x-π)的周期。 点击获取更多步骤... ...
+ \sin x \cos x = 0\$ (1) (1) \$\sin ( \pi + x ) \cos ( - x ) + \sin ( 2 \pi - x ) \cos ( \pi - x )\$ \$= ( - \sin x ) \cos x + \sin ( - x ) ( - \cos x )\$ \$= - \sin x \cos x + ( - \sin x ) ( - \cos x )\$...
回答：原式=sin(-x)=-sinx