std::copyable_function 在标头<functional>定义 template<class...> classcopyable_function;// 未定义 (1)(C++26 起) template<classR,class...Args> classcopyable_function<R(Args...)>; template<classR,class...Args> classcopyable_function<R(Args...)noexcept>; ...
#include <memory> #include <functional> class A{ //non-copyable std::unique_ptr<int> a; public: void operator()(){} //non-const }; void func(std::function<void(void)> f) {} int main() { A fobj; func(fobj); return 0; } 如上,需要传递一个A的函数对象给func,并且fobj不能是...
Solved: Hi, I tried to create a tbb::flow::function_node on a move-only type, e.g. #include class MyType { public: MyType() = default; MyType(const
std::copyable_function Defined in header<functional> template<class...> classcopyable_function;// not defined (1)(since C++26) template<classR,class...Args> classcopyable_function<R(Args...)>; template<classR,class...Args> classcopyable_function<R(Args...)noexcept>; ...