在上面的Dockerfile示例中,/path/to/source/directory是源目录,/path/in/docker/image/是目标目录。COPY指令会将源目录及其所有子目录和文件复制到目标目录中。 4. 构建Docker镜像 使用docker build命令来构建Docker镜像。例如,如果你的Dockerfile位于当前目录中,并且你想要将镜像标记为my-image,你可以使用以下命令: ...
Copy files/folders between a container and the local filesystem Use ‘-‘ as the source to read a tar archive from stdin and extract it to a directory destination in a container. Use ‘-‘ as the destination to stream a tar archive of a container source to stdout. 扩展说明🔗 在容器和...
docker build -t cyq/chydapp . 创建镜像,其中“.”代表dockerfile所在目录为当前目录 docker images docker ispect cyq/chydapp 查看镜像元信息 docker ps docker run -p 8080:8080 cyq/chydapp docker run --entrypoint="ls" cyq/chydapp 覆盖dockerfile里的ENTRYPOINT docker run --entrypoint="" cyq/ch...
是.dockerignore引起的，.dockerignore 中有下面的配置
To convert to a many-to-many copy, you cannot use Dockerfile syntax. You must have a single destination directory on the right side, even if your source is one or more directories. Keep in mind that Docker will copy the contents of those directories, not the directory name itse...
<src>路径必须在构建的上下文内部;您不能执行COPY ../something /something,因为docker build的第一步是将上下文目录(和子目录)发送到 docker 守护进程。 If<src>is a directory, the entire contents of the directory are copied, including filesystem metadata. ...
whereas when I build my dockerfile locally, the last argument (the context) I would give to docker build is my root directory (/project), not /project/docker. So is there a way to get around this, or does using spotty mean that I need to keep my dockerfile in my root directory?
【Docker】Dockerfile之COPY 【Docker】Dockerfile之COPY 环境 1. virtual box 6.1 2. centos 7.8 3. docker 19.03 COPY COPY has two forms:COPY 指令有两种格式 COPY [--chown=<user>:<group>] <src>... <dest> COPY [--chown=<user>:<group>] ["<src>",... "<dest>"]This latter form...
Dockerfile中“copy时报no such file or directory”问题的解决 在使用Docker构建镜像的过程中,我们经常会遇到“copy时报no such file or directory”的错误。这个问题通常是由于在Dockerfile中使用COPY命令时,指定的文件或目录不存在导致的。本文将详细介绍如何避免和解决这个问题。
是.dockerignore引起的，.dockerignore 中有下面的配置