意思是double类型数据转化成int类型数据精度会丢失，int类型是没有小数部分的，你在程序中使用了强制转换或者赋值运算符=左边是int型，右边是double型也会出现这种警告，但不影响程序的运行，但有可能影响到结果
private double ConvertToDouble(string s) { char systemSeparator = Thread.CurrentThread.CurrentCulture.NumberFormat.CurrencyDecimalSeparator[0]; double result = 0; try { if (s != null) if (!s.Contains(",")) result = double.Parse(s, CultureInfo.InvariantCulture); else result = Convert.ToDouble...
#include <iostream> #include <sstream> double convert(std::string string) { std::stringstream s(string); double ret = 0; s >> ret; return ret; } int main() { std::cerr << convert("0.03456") << std::endl; std::cerr << convert("0.1889") << std::endl; std::cerr << conver...
for some calculation and some eventual truncation led to the system going haywire. So my question is, given this code: int main() { float f = 59.89F; /* the following line caused problems */ double d = f; /* they ended up solving it like this */ f *= 1000.0; double dd = (do...
Converting double[] To IntPtr and then to Byte Array Converting from byte[] to IntPtr Converting from List<Model> to List<string> Converting Hexadecimal String to Unicode Converting HexString (representing FloatValue) to floating point converting images into hexadecimal Converting JSON to Dictionary ...
Double. getch() at the end is only to pause the screen so you can see the result. #include <conio.h> #include <iostream> using namespace std; void main () { string S ; // S = "990123"; double D = double(); D = atoi( S.c_str()); cout << D << " <--- Interger St...
I am trying to convert a double type into an integer; which in itself isn't too much of a problem. The problem I am facing is trying to round my numbers, I would use the round() function however, when a number is exactly halfway (1.5) for example I would like it to round down...
These, when cast to short and then sign-extended back to int are -1 and 0, respectively. Proposed Fix The .NET Runtime should correctly account for overflow and return a "correct" value in this scenario. On x86, the "indefinite integer value" is defined to be: (2^(w-1), where w...
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My way of going about this is to use a self-made getstrn function and plug that into another function which would convert the string into a double. My safe get string: void safeGetString(char arr[], int limit){ int c, i; i = 0; c = getchar(); while (c != '\n'){ if (...