Interval Notation: (-∞,1)∪(1,∞) Use each root to create test intervals. $$ x \leq - 3 $$ $$ - 3 1 $$ Choose a test value from each interval and pl ug this value into the original inequality to de termine which intervals satisfy the inequality. x1True T he solution consi...
Add ( 1) to both sides of the equation. ( x=1) Solve for each factor to find the values where the absolute valueexpression goes from negative to positive. ( x=-3) ( x=1) Consolidate the solutions. ( x=-3,1) Find the domain of ( (x+3)/(x-1)). Interval Notati...
Convert to Interval Notation (x-7)/(x+8)<=0x−7x+8≤0x-7x+8≤0 Find all the values where the expression switches from negative to positive by setting each factor equal to 00 and solving. x−7=0x-7=0 x+8=0x+8=0Add 77 to both sides of the equation. x=7x=7...
xby1. x>-10-5 x>-10-5 x>-10-5 -10by-5. x>2 x>2 x>2x>2 Convert theinequalitytointervalnotation. (2,∞)(2,∞) −5x−2<−12-5x-2<-12 ( ) | [ ] √ ≥ 7 8 9
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( w=-2/w) Solve the secondequation for ( w). ( w=i√2,-i√2) The solution to the equation includes both the positive and negative portions of the solution. ( w=√2,-√2,i√2,-i√2) Convert the inequality to interval notation. ( [2,2]) 反馈...
【解析】 If any individual factor on the left side of th e equation is equal to o, the entire expression will be equal to o. $$ x - 4 = 0 $$ $$ x - 6 = 0 $$ $$ x - 7 = 0 $$ Set the first factor equal to o and solve. $$ x = 4 $$ Set the next factor equal...
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To write-3as awith a,by1111. f≤-1311-3⋅1111 -3and1111. f≤-1311+-3⋅1111 f≤-13-3⋅1111 -3by11. f≤-13-3311 Subtract33from-13. f≤-4611 f≤-4611 f≤-4611 f≤−4611f≤-4611 Convert theinequalitytointervalnotation. ...
Convert theinequalitytointervalnotation. (−6,6)(-6,6) |7x|<42|7x|<42 ( ) | [ ] √ ≥ 7 8 9 ≤ 4 5 6 / ^ × > α µ 1