通过以上步骤,你应该能够解决“failed to convert parameter value from a jobject to a string”的错误。如果问题仍然存在,建议仔细检查JNI环境的设置以及所有相关的代码逻辑。
public RecuperoStampaCodici(JObject responseSearch) { try { string code = String.Empty; string licensecode = String.Empty; string locationId = String.Empty; //Scrivo i valori aggiornati di access_token e refresh_token foreach (var valueJson in responseSearch) { if (valueJson.Key.Equals("C...
It easily converts a C# object to a JSON string. The object name is passed as a parameter to this method. The correct syntax to use this method is as follows: JObject.FromObject(ObjectName); Example Code: using System; using Newtonsoft.Json.Linq; namespace JSONConversion { public cla...
If the above achieve your requirement, you could also refer the following code, useJObject.Parsemethod to parse a JSON string, which will get the same result. var value = "{ \"value\": \"example\", \"source\":15}"; var result2 = JObject.Parse(value); ...
Atleast one checkbox is compulsory to be checked Attempt by method 'Microsoft.VisualBasic.CompilerServices.Symbols+Container.InvokeMethod(Method, System.Object[], Boolean[], System.Reflection.BindingFlags)' to access method 'System.Data.Common.DataRecordInternal.get_Item(System.String)' failed. Attempted...
For example, we have string json = @" { 'company': { 'name': 'abc', 'address': 'summer street' } }"; JObject j = JObject.Parse(json); JObject c = (JObject)j["customer"]; if (c != null) { string name = (string)c["name"]; } this works fine...
JObject obj= array[i]asJObject;intid = Convert.ToInt32(obj["id"]);vartitle = obj["title"]; } Json转DataTable 1stringjson =@"[2{ id: 1, title: '必订款', no: 'bdk', flag_ka: 'y' },3{ id: 2, title: '必订规格', no: 'bdgg', flag_ka: 'n' }4]";5Newtonsoft.Jso...
问将Newtonsoft.Json.JsonConvert.DeserializeObject转化为Newtonsoft.Json.Linq.JObject问题EN我从文件中读取...
本篇主要讲的的是如何通过使用Newtonsoft.Json中的JsonConvert.DeserializeObject(string value)方法将对应的JSON字符串转化为指定的.NET对象类型数据...{ public bool status { get; set; } pu...
dt= (objectType ==typeof(DataTable)) ?newDataTable() : ((DataTable)Activator.CreateInstance(objectType)); }if(reader.TokenType ==JsonToken.PropertyName) { dt.TableName= (string)reader.Value; reader.Read(); }if(reader.TokenType ==JsonToken.StartArray) ...