TreeNode * parent = temp.front(); temp.pop(); if(len>0){t =newTreeNode(0);parent->left = t;temp.push(t);len--;} elsebreak; if(len>0){t =newTreeNode(0);parent->right = t;temp.push(t);len--;} elsebreak; } vector<TreeNode *>treev; treev.push_back(THead); TreeNode...
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. Top down 的解题方法: 1. 将LinkedList的值保存到一个数组中,转化成Convert Sorted Array to Binary Search Tree 来解决 时间复杂度为O(n), 空间复杂度为O(n) 1/**2* Definition for sin...
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1. Example: AI检测代...
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1. Example: Given th...
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.Example...
伪代码 代码 funcsortedListToBST(head*ListNode)*TreeNode{nums:=make([]int,0)forhead!=nil{nums=append(nums,head.Val)head=head.Next}returntobst(nums)}functobst(nums[]int)*TreeNode{iflen(nums)==0{returnnil}k:=len(nums)/2node:=&TreeNode{Val:nums[k]}node.Left=tobst(nums[:k])node....
classSolution{public:TreeNode*sortedListToBST(ListNode*head){returncreate(head,NULL);}TreeNode*create(ListNode*head,ListNode*tail){if(head==tail)returnNULL;ListNode*slow=head,*fast=head;while(fast!=tail&&fast->next!=tail)slow=slow->next,fast=fast->next->next;TreeNode*root=newTreeNode(slow-...
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 这道题是要求把有序链表转为二叉搜索树,和之前那道Convert Sorted Array to Binary Search Tree 将有序数组转为二叉搜索树思路完全一样,只不过是操作的数据类型有所差别,一个是数组,一个是链表...
a height balanced BST BST的中序遍历是一个sorted-array,再构造回去成一个BST,先将中间的元素作为根节点,这个节点的左右分别是左子树和右子树。如此递归地...
問題: https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/description/ 次に解く問題: https://leetcode.com/problems/path-sum/ ファイルの構成 problems/src/<解いた問題名>/以下にstep1~step3のファイルを保存しています