Given an array where elements are sorted in ascending order, convert it to a height balanced BST. Solution: 1/**2* Definition for binary tree3* public class TreeNode {4* int val;5* TreeNode left;6* TreeNode righ
TreeNode* sortedArrayToBST(vector<int>& nums,intstart,intend){if(start > end)returnnullptr;intmid = (start + end) /2; TreeNode*root =newTreeNode(nums[mid]); root->left = sortedArrayToBST(nums, start, mid -1); root->right = sortedArrayToBST(nums, mid +1, end);returnroot; } ...
LeetCode 109. Convert Sorted List to Binary Search Tree Description Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtr...
Given an integer arraynumswhere the elements are sorted inascending order, convertit to aheight-balancedbinary search tree. Example 1: Input:nums = [-10,-3,0,5,9]Output:[0,-3,9,-10,null,5]Explanation:[0,-10,5,null,-3,null,9] is also accepted: Example 2: Input:nums = [1,3]...
leetcode 108. Convert Sorted Array to Binary Search Tree,Givenanarraywhereelementsaresortedinascendingorder,convertittoaheightbalancedBST.Forthisproblem,aheight-balancedbinarytreeisdefinedasabinarytreeinwhichthedepthofthet
Leetcode 之Convert Sorted Array to Binary Search Tree(54),思路很简单,用二分法,每次选中间的点作为根结点,用左、右结点递归。TreeNode*sortedArrayToBST(vector<int>&num){returnsortedArrayToBST(num.begin(),num.end());}template<typename
My code: /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public TreeNode sortedArrayToBST(int[] nums) { ...
大概思路是要做一个root, 一个left subtree, right subtree. 但是我一开始只有一个function,我发现要recursion的时候, array不是很好取middle point。 因为比如最开始Array是[1,3,4,5,6,7,8,9]. 第一次mid point拿到root以后,要把middle point的左右分成两个子array 继续recursion, 类似[1,3,4,5], [7...
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1. ...
LeetCodeの制約ではlen(nums) >= 1が保証されてますが、空配列だとIndexErrorになりますね。 👍 1 arai60/21-29_Tree_BT_BST/24_108_Convert Sorted Array to Binary Search Tree/level_3.py def helper(left, right): if left > right: return None mid = (left + right) // 2 hay...