}privateTreeNode sortedListToBST(intlistSize) {//in-order traversalif(listSize <= 0)returnnull; TreeNode left= sortedListToBST(listSize / 2); TreeNode root=newTreeNode(current.val); current=current.next; TreeNode right= sortedListToBST(listSize - 1 - listSize / 2); root.left=left;...
然后inorder traversal填进去就可以。
public List<Integer> inorderTraversal(TreeNode root) { List<Integer> ans = new ArrayList<>(); getAns(root, ans); return ans; } private void getAns(TreeNode node, List<Integer> ans) { if (node == null) { return; } getAns(node.left, ans); ans.add(node.val); getAns(node.right...
cout<<"\nend of level:"<<count<<endl;}intmain(){intn,no;cout<<"enter no of elements\n";cin>>n;vector<int>v;cout<<"enter the sorted array\n";while(n--){cin>>no;v.push_back(no);}TreeNode*root=sortedArrayToBST(v);cout<<"displaying level order traversal\n";levelOrder(root)...
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees ofeverynode never differ by more than 1. ...
C# program to implement Post-order traversal in Binary Tree C# program to get all stack frames using StackTrace class C# program to traverse the singly linked list C# program to delete a given node from the singly Linked-List C# program to demonstrate the Tower Of Hanoi ...
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1. ...
Binary Search Tree Iterator 74 -- 1:31 App Leetcode-0081. Search in Rotated Sorted Array II 84 -- 2:53 App Leetcode-0144. Binary Tree Preorder Traversal 63 -- 4:35 App Leetcode-0101. Symmetric Tree 7 -- 1:29 App Leetcode-0167. Two Sum II - Input Array Is Sorted 12...
Binary Tree Inorder Traversal https://leetcode.com/problems/binary-tree-inorder-traversal/description/ Convert Binary Search Tree (BST) to Sorted Doubly-Linked List in order. 这是fb的一个高频题 这题的解法主要参考网上的资料...leetcode-426-Convert Binary Search Tree to Sorted Doubly Linked List...
voidinorder(Node*root,queue<int>&keys) { if(root==nullptr){ return; } inorder(root->left,keys); keys.push(root->data); inorder(root->right,keys); } // Function to perform preorder traversal on a given binary tree. // Assign each encountered node with the next key from the queue...