Solve the equation in Step 5 for r by dividing through both sides of the equation by (3cos θ -2sin θ). You find that r= 7/(3cos θ -2sin θ). This is the polar form of the rectangular equation in Step 3. This form is useful when you need to graph a function in terms of...
Convert the rectangular equation to polar equation.Consider, the rectangular equation,x^2+y^2=6x ... (1)The relationship between rectangular coordinate (x,y) system and polar coordinate (r,θ )system is:.(align) x=rcos θ y=rcos θ (align)\)...(2)Consider, the rectangular equation,x...
Answer to: Convert the rectangular equation x^2 + y^2 - 2y = 0 to polar form. By signing up, you'll get thousands of step-by-step solutions to your...
Convert the rectangular equation (x2+y2)2−4(x2−y2)=0 to polar form. Convert the polar equation r=4cosθ to rectangular form. Polar To Rectangular Coordinates 1) To convert from Rectangular Coordinates (x,y) to Pola...
百度试题 结果1 题目【题目】Convert the polar equation to rectangular form.r= 7 sec(A) 相关知识点: 试题来源: 解析 【解析】 反馈 收藏
百度试题 结果1 题目Convert (−4,0) to polar form.相关知识点: 试题来源: 解析 SAMPLE ANSWER: (4,π) SAMPLE ANSWER: (4,π) 反馈 收藏
There are 2 steps to solve this one. Solution Share Step 1 Given equation in polar form: r=cotθ⋅cscθ Explanation: Trigonometric functions cotθ and cscθ are defined in terms of sine and cosine ...View the full answer Step 2 Unlock Answer Unlo...
To convert the complex number z=i−1cos(π3)+isin(π3) into polar form, we will follow these steps: Step 1: Identify the DenominatorThe denominator can be expressed using Euler's formula:cos(π3)+isin(π3)=eiπ3Calculating the values:cos(π3)=12,sin(π3)=√32Thus, the denominato...
Convert of the complex number in the polar form: - 3 07:16 Solve the equation -x^2+x-2=0 03:36 Solve the equation:sqrt(2)x^2+x+sqrt(2)=0 02:59 Solve the equation:x^2-x+2=0 03:00 Solve the equation: x^2+3=0 03:15 Solve the equation:x^2+3x+9=0 03:26 Solve the...
Complex numbers: convert the exponential to polar form Summary:: Hello, my question asks if the complex exponential equation 4e^(-j) is equal to 4 ∠-180°. I tried to use polar/rectangular conversions: a+bj=c∠θ with c=(√a^2 +b^2) and θ=tan^(-1)[b/a] 4e^(-j)=4 ∠-...