使用一个vector将所有节点的值以升序排列。然后比较,求和,加上。 3、代码 1TreeNode* convertBST(TreeNode*root) {2if(root ==NULL)3returnNULL;45vector<int>v;6inorder(root,v);7increaseVal(root, v);89returnroot;1011}1213voidincreaseVal(TreeNode *root, vector<int> &v)14{15if(root ==NULL)...
convertBST(root -> right); sum += root -> val; root -> val = sum; convertBST(root -> left); returnroot; } };
Given the root of a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. As a reminder, abinary search treeis a tree that satisfies th...
BST是左子树小于右子树。 中序便利会输出他的从达到小的顺序。 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ classSolution{ public: intsum=0,now...
Convert a BST to a sorted circular doubly-linked list in-place. Think of the left and right pointers as synonymous to the previous and next pointers in a doubly-linked list. Let's take the following BST as an example, it may help you understand the problem better: ...
LeetCode 109. Convert Sorted List to Binary Search Tree Description Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtr...
LeetCode 109. Convert Sorted List to BST 简介:给定一个链表,其中元素按升序排序,将其转换为高度平衡的BST。对于这个问题,高度平衡的二叉树被定义为:二叉树中每个节点的两个子树的深度从不相差超过1。 Description Given a singly linked list where elements are sorted in ascending order, convert it to a ...
Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 递归法 复杂度 时间O(N) 空间 O(H) 思路 和用链表建树的思路相似,实现更加简单,因为数组支持随机查询,我们可以直接访问中点而无须遍历链表。
LeetCode 108. Convert Sorted Array to Binary Search Tree Description Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balancedbinary treeis defined as a binary tree in which the depth of the two subtrees of every ...
利用好BST的特性,解起来并不难 1/**2* Definition for a binary tree node.3* public class TreeNode {4* int val;5* TreeNode left;6* TreeNode right;7* TreeNode(int x) { val = x; }8* }9*/10publicclassSolution {11privateintsum = 0;12publicTreeNode convertBST(TreeNode root) {13if...