LeetCode 109. Convert Sorted List to Binary Search Tree Description Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balan
简介:给定一个链表,其中元素按升序排序,将其转换为高度平衡的BST。对于这个问题,高度平衡的二叉树被定义为:二叉树中每个节点的两个子树的深度从不相差超过1。 Description Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a h...
leetcode--Convert Sorted List to Binary Search Tree 1.题目描述 Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 2.解法分析 题意为将一个按升序排列的单链表转换为一个平衡的BST,将单链表转换为平衡树很容易,然后按照先序遍历赋值即可。时...
Leetcode-Convert Sorted Array to BST Given an array where elements are sorted in ascending order, convert it to a height balanced BST. Solution: 1/**2* Definition for binary tree3* public class TreeNode {4* int val;5* TreeNode left;6* TreeNode right;7* TreeNode(int x) { val = x...
Given an integer arraynumswhere the elements are sorted inascending order, convertit to aheight-balancedbinary search tree. Example 1: Input:nums = [-10,-3,0,5,9]Output:[0,-3,9,-10,null,5]Explanation:[0,-10,5,null,-3,null,9] is also accepted: ...
leetcode 108. Convert Sorted Array to Binary Search Tree,Givenanarraywhereelementsaresortedinascendingorder,convertittoaheightbalancedBST.Forthisproblem,aheight-balancedbinarytreeisdefinedasabinarytreeinwhichthedepthofthet
LeetCode 109 Convert Sorted List to Binary Search Tree Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees ofevery...
we don't need to take care of its left and right tree which means they are null. SO: 4 -> 5 begin = 4; end = 5; mid = 4 ... 基本是相同的流程,然后就可以写出一个DFS出来。 下面复习下,什么是 balanced bst bst 的问题就在于树的结构根据输入结果的顺序而变化,不可人为控制,导致经常性...
root.right = getBST(mid + 1, end, nums); return root; } } My test result: Paste_Image.png 这道题目和上面的一个想法.具体就不细说了。 ** 总结: sorted array -> balanced bst ** Anyway, Good luck, Richardo! My code: /**
a height balanced BST BST的中序遍历是一个sorted-array,再构造回去成一个BST,先将中间的元素作为根节点,这个节点的左右分别是左子树和右子树。如此递归地...