TreeNode*sortedArrayTree(vector<int> arr,intstart,intend) {if(start > end)returnNULL; TreeNode*root =newTreeNode(arr[(start + end)/2]); root-> left = sortedArrayTree(arr, start, (start + end)/2-1); root-> right = sortedArrayTree(arr, (start + end)/2+1, end);returnroot; ...
1/**2* Definition for singly-linked list.3* public class ListNode {4* int val;5* ListNode next;6* ListNode(int x) { val = x; next = null; }7* }8*/9/**10* Definition for binary tree11* public class TreeNode {12* int val;13* TreeNode left;14* TreeNode right;15* TreeNode...
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1. Example: Given th...
Given an integer arraynumswhere the elements are sorted inascending order, convertit to aheight-balancedbinary search tree. Example 1: Input:nums = [-10,-3,0,5,9]Output:[0,-3,9,-10,null,5]Explanation:[0,-10,5,null,-3,null,9] is also accepted: Example 2: Input:nums = [1,3]...
题目描述(简单难度) 给一个升序数组,生成一个平衡二叉搜索树。平衡二叉树定义如下: 它是一棵空树或它的左右两个子树的高度差的绝对值不超过1,并且左右两个子树都是一棵平衡二叉树。 二叉搜索树定义如下: 若…
leetcode-109-Convert Sorted List to Binary Search Tree error: cannot solve it. pattern: left open, right close for current search range convert(head, tail): if(head == tail) return nullptr; mid = find(head, tail); TreeNode *tree_mid = new TreeNode(mid->val);...
Binary Search Tree Iterator 74 -- 1:31 App Leetcode-0081. Search in Rotated Sorted Array II 84 -- 2:53 App Leetcode-0144. Binary Tree Preorder Traversal 63 -- 4:35 App Leetcode-0101. Symmetric Tree 7 -- 1:29 App Leetcode-0167. Two Sum II - Input Array Is Sorted 12...
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.Example:1.一看之下感觉和108很像，后来发现是linklist，就又不会做了=。=于是在youtube上找到了公瑾讲解 2.这道题...
* Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */publicclassSolution{public TreeNodesortedListToBST(ListNode head){if(head==null)returnnull;int total=1;ListNode temp=head;while(tem...
public: TreeNode *sortedArrayToBST(vector<int> &num) { return create(num,0,num.size()-1); } TreeNode* create(vector<int>num,int L,int R) { if(L>R)return NULL; int mid=(R+L+1)/2; //BST树总是从左到右排满的,如果不优先选右边的这个,{1,3}结果为{1,#,3},而实际结果应为...