#include<iostream>#include<new>#include<vector>#include<cmath>usingnamespacestd;//Definition for binary treestructTreeNode {intval; TreeNode*left; TreeNode*right; TreeNode(intx) : val(x), left(NULL), right(NULL) {} };classSolution {public: TreeNode*sortedArrayToBST(vector<int> &num) {...
https://oj.leetcode.com/problems/convert-sorted-array-to-binary-search-tree/ Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 解题思路: 回忆一下BST二叉搜索树的定义,他是这样一个二叉树,他的顶节点比左节点大,比右节点小,同时他的左子树和右子树...
public TreeNode sortedArrayToBST(int[] nums) { return sortedArrayToBST(nums, 0, nums.length); } private TreeNode sortedArrayToBST(int[] nums, int start, int end) { if (start == end) { return null; } int mid = (start + end) >>> 1; TreeNode root = new TreeNode(nums[mid])...
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees ofeverynode never differ by more than 1. Example: AI检测代码解析 Given th...
Can you solve this real interview question? Convert Sorted Array to Binary Search Tree - Given an integer array nums where the elements are sorted in ascending order, convert it to a height-balanced binary search tree. Example 1: [https://assets.lee
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 数组的中点肯定就是平衡BST的根节点,以此规律递归。 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; ...
Binary Tree Preorder Traversal 63 -- 4:35 App Leetcode-0101. Symmetric Tree 7 -- 1:29 App Leetcode-0167. Two Sum II - Input Array Is Sorted 12 -- 5:37 App Leetcode-0033. Search in Rotated Sorted Array 5 -- 2:23 App Leetcode-0026. Remove Duplicates from Sorted Array ...
public: TreeNode *sortedArrayToBST(vector<int> &num) { return create(num,0,num.size()-1); } TreeNode* create(vector<int>num,int L,int R) { if(L>R)return NULL; int mid=(R+L+1)/2; //BST树总是从左到右排满的,如果不优先选右边的这个,{1,3}结果为{1,#,3},而实际结果应为...
解析 高度平衡,保险起见,左右节点个数相同且均衡分配即可。二叉树问题还是递归问题,将数组分割成左右两个部分,然后递归求解即可。 伪代码 root=mid(nums)root.left=f(nums[:half])root.Right=f(nums[half+1:]) 代码 funcsortedArrayToBST(nums[]int)*TreeNode{iflen(nums)==0{returnnil}k:=len(nums)/2...
Multi-dimensional array cannot be converted to an expression tree Multiple initializations of '<membername>' 'MustInherit' cannot be specified for partial type '<partialtypename>' because it cannot be combined with 'NotInheritable' specified for one of its other partial types 'MustOverride' cannot be...