MismatchedMethodSig.java:6: error: method greetPerson in class MismatchedMethodSig cannot be applied to given types; greetPerson(123); ^ required: String found: int reason: argument mismatch; int cannot be converted to String(d) 1 2 3 4 5 6 7 8 9 10 11 12 package rollbar; public...
针对你遇到的错误信息“error: constructor people in class people cannot be applied to given types”,这通常意味着在尝试创建People类的对象时,提供的参数与People类中定义的构造函数所需要的参数不匹配。以下是一些可能的解决步骤和示例: 检查People类的构造函数定义: 首先,你需要查看People类中构造函数的定义。
TestClass.java:24: error: constructor Shapesinclass Shapes cannot be applied to given types; Shapes Shape1 = new Shapes(); //Error will occor here. ^ required: double found: no arguments reason: actual and formal argument lists differinlength 此错误 Shapes 类中的构造函数 Shapes 无法应用于给...
Remove thevoidkeyword from both constructors, that should do the trick. Constructors don't require a return type in Java. Elijah Kamski Member 564 8 PostedMay 27, 2022 Hi there, I'm making a piece of code that simply stores objects of the class Users. ...
/Users/Andrea/Progetti/ionic-app/platforms/android/app/src/main/java/org/apache/cordova/firebase/FirebasePluginMessagingService.java:120: error: constructor Builder in class Builder cannot be applied to given types; NotificationCompat.Builder notificationBuilder = new NotificationCompat.Builder(this, channel...
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classEmployee{publicEmployee(Stringname){}} If we try to create an instance ofEmployeeusing the default constructor, then a compilation error will occur: Employeeemployee=newEmployee();//'Employee(java.lang.String)' in 'Employee' cannot be applied to '()' ...
Invocation of Base Class Constructor in Java Like C++, Java insists that a constructor for a base class be called before the constructor for a derived class. The syntax is a bit simpler, however; the initial line of the code for the derived class constructor may consist of a “call” to...
mArray = new std::string[in_array.mSize]; std::copy(in_array.mArray, in_array.mArray + mSize, mArray); } return *this; } Given the aforementioned Array class, the following code demonstrates when the various methods will be called. Array a; // default constructor Array a(10); /...
Initializes a new instance of the JavaScriptSerializer class that has no type resolver. C# コピー public JavaScriptSerializer (); Remarks An instance of the JavaScriptSerializer class without a type resolver does not include type metadata properties (named "__type") in the serialized JSON string....