publicTreeNode buildTree(int[] preorder,int[] inorder) { if(preorder ==null|| inorder ==null|| preorder.length ==0 || preorder.length != inorder.length) { returnnull; } intlen = preorder.length; TreeNode root = buildHelper(preorder,0, len -1, inorder,0, len -1); returnr...
0,preorder.length,inorder,0,inorder.length);}privateTreeNodebuildTreeHelper(int[]preorder,intp_start,intp_end,int[]inorder,inti_start,inti_end){// preorder 为空,直接返回 nullif(p_start==p_end){returnnull;}introot_val=preorder[p_start];TreeNoderoot=newTreeNode(root_val);//在中序遍...
1publicclassSolution {2publicTreeNode buildTree(int[] inorder,int[] postorder) {3//IMPORTANT: Please reset any member data you declared, as4//the same Solution instance will be reused for each test case.5if(inorder ==null||postorder ==null||inorder.length == 0||postorder.length==0)6...
TreeNode* root= new TreeNode(preorder[preorder_left]); int left_size = inorder_root - inorder_left; //获取左子树的大小 //preorder_left+1---preorder_left+left_size是preorder的左子树位置,对应inordered左子树位置为inorder_left---inorder_root-1。preorder边界是来确定左子树的左右子树边界,...
Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 方法 依据树的中序遍历和前序遍历,来构造树。使用递归的思想。 TreeNode getTree(int[] preorder, int preStart, int preEnd, int[] inorder, int inStar...
(inorder,0,len-1,postorder,0,len-1,map);}publicTreeNodehelper(int[]inorder,ints1,inte1,int[]postorder,ints2,inte2,Map<Integer,Integer>map){if(s2>e2)returnnull;TreeNodenode=newTreeNode(postorder[e2]);if(s2==e2)returnnode;intinPos=map.get(postorder[e2]);intnumLeft=inPos-s1;node....
* function TreeNode(val) { * this.val = val; * this.left = this.right = null; * } *//** * @param {number[]} inorder * @param {number[]} postorder * @return {TreeNode} */varbuildTree=function(inorder,postorder){varn=inorder.lengthif(n===0||postorder.length===0)returnnull...
105. Construct Binary Tree from Preorder and Inorder Traversal——tree,程序员大本营,技术文章内容聚合第一站。
printf("\npostorder traversal of tree\n"); postorder(root); break; case 2: insert(); printf("\npreorder traversal of tree\n"); preorder(root); printf("\nInorder traversal of tree\n"); inorder(root); printf("\npostorder traversal of tree\n"); postorder(root); break; default:prin...
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ classSolution{ public: TreeNode*buildTree(vector<int>& preorder,vector<int>& inorder){ returndfs(preorder,inorder,0,preorder.size()-1,0,inorder.size()-1); ...