publicTreeNodebuildTree(int[]preorder,int[]inorder){returnbuildTreeHelper(preorder,inorder,(long)Integer.MAX_VALUE+1);}intpre=0;intin=0;privateTreeNodebuildTreeHelper(int[]preorder,int[]inorder,longstop){//到达末
publicTreeNode buildTree(int[] preorder,int[] inorder) { if(preorder ==null|| inorder ==null|| preorder.length ==0 || preorder.length != inorder.length) { returnnull; } intlen = preorder.length; TreeNode root = buildHelper(preorder,0, len -1, inorder,0, len -1); returnr...
}privateTreeNode buildTree(int[] preorder,intpreLo,intpreHi,int[] inorder,intinLo,intinHi) {if(preLo > preHi || inLo >inHi)returnnull; TreeNode root=newTreeNode(preorder[preLo]);introotAtInorder = 0;for(inti = inLo; i <= inHi; i++) {if(inorder[i] == root.val) {//...
public TreeNode Core(int[] preorder, int[] inorder, int preLeft, int preRight, int inLeft, int inRight){ //base case: 取决于当前条件 if(preLeft==preRight){ return new TreeNode(preorder[preLeft]); } //找出根节点: 前序遍历的第一个元素就是根节点的val TreeNode root = new TreeNo...
map.put(inorder[i],i); } return helper(preorder,0,preorder.length-1,inorder,0,inorder.length-1, map); } private TreeNode helper(int[] preorder, int preL, int preR, int[] inorder, int inL, int inR, HashMap<Integer, Integer> map) ...
intsearchNode(intinorder[],intinorderSize,intkey){inti;for(i=0;i<inorderSize;i++){if(key==inorder[i]){returni;}}return-1;}structTreeNode*buildTree(int*preorder,intpreorderSize,int*inorder,intinorderSize){if(preorder==NULL||inorder==NULL||preorderSize==0||inorderSize==0)return...
Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 翻译:给定树的前序和中序遍历,构造二叉树。 注意: 树中不存在重复项。 思路:首先,你应该知道 前序遍历:根节点,左子树,右子树; ...
105. Construct Binary Tree from Preorder and Inorder Traversal——tree,程序员大本营,技术文章内容聚合第一站。
题目: Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 根据前序遍历和中序遍历结果构造二叉树。 思路分析: 分析二叉树前序遍历和中序遍历的结果我们发现: 二叉树前序遍历的第一个节点是根节点。 在中序遍历...
# Definition for a binary tree node. # class TreeNode(object): # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution(object): def buildTree(self, preorder, inorder): """ :type preorder: List[int] :type inorder: List[int] :...