Given preorder and inorder traversal of a tree, construct the binary tree. 本题就是根据前序遍历和中序遍历的结果还原一个二叉树。 题意很简答,就是递归实现,直接参考代码吧。 查询index部分可以使用Map做查询,建议和下一道题 leetcode 106. Construct Binary Tree f
publicTreeNodebuildTree(int[]preorder,int[]inorder){returnbuildTreeHelper(preorder,0,preorder.length,inorder,0,inorder.length);}privateTreeNodebuildTreeHelper(int[]preorder,intp_start,intp_end,int[]inorder,inti_start,inti_end){// preorder 为空,直接返回 nullif(p_start==p_end){returnnull;...
Given inorder and level-order traversals of a Binary Tree, construct the Binary Tree. Following is an example to illustrate the problem. BinaryTree Input: Two arrays that represent Inorder and level order traversals of a Binary Tree in[] = {4, 8, 10, 12, 14, 20, 22}; level[] = {...
publicclassBuildTreeFromPreorderAndInorder { publicTreeNode buildTree(int[] preorder,int[] inorder) { if(preorder ==null|| inorder ==null|| preorder.length ==0 || preorder.length != inorder.length) { returnnull; } intlen = preorder.length; TreeNode root = buildHelper(preorder,0,...
current->right=build(p_l+left_tree_n+1,p_r,k+1,i_r); return current; } TreeNode* buildTree(vector<int>& preorder, vector<int>& inorder) { if(preorder.empty())return NULL; return build(preorder.begin(),preorder.end()-1,inorder.begin(),inorder.end()-1); ...
* TreeNode right; * TreeNode(int x) { val = x; } * } */publicclassSolution{public TreeNodebuildTree(int[]preorder,int[]inorder){if(preorder==null||preorder.length==0)returnnull;if(inorder==null||inorder.length==0)returnnull;if(preorder.length!=inorder.length)returnnull;returnbui...
Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 翻译:给定树的前序和中序遍历,构造二叉树。 注意: 树中不存在重复项。 思路:首先,你应该知道 前序遍历:根节点,左子树,右子树; ...
题目: Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 根据前序遍历和中序遍历结果构造二叉树。 思路分析: 分析二叉树前序遍历和中序遍历的结果我们发现: 二叉树前序遍历的第一个节点是根节点。 在中序遍历...
105.ConstructBinaryTreefromPreorderandInorderTraversalFor example, given:Returnthe...fromInorderandPostorderTraversalgivenReturnthefollowingbinarytree: 同样以上面的图为例来说明: class binary tree traversal -Preordertraversalroot -> left -> right -Inordertraversalleft -> root -> right - Postorder trav...
# Definition for a binary tree node. # class TreeNode(object): # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution(object): def buildTree(self, preorder, inorder): """ :type preorder: List[int] :type inorder: List[int] :...