if (is_this_parameter (x)) { if (DECL_CONSTRUCTOR_P (DECL_CONTEXT (x))) { if (flags & tf_error) sorry ("calling a member function of the " "object being constructed in a constant " "expression"); return false; } /* Otherwise OK. */; } else if (!potential_constant_expression...
if (is_this_parameter (x)) { if (DECL_CONSTRUCTOR_P (DECL_CONTEXT (x))) { if (flags & tf_error) sorry ("calling a member function of the " "object being constructed in a constant " "expression"); return false; } /* Otherwise OK. */; } else if (!potential_constant_expression...
constexpr int f2(NL) { // Error, the parameter type NL is not a literal type. return 55; } constexpr S f3() { return S(); } enum { val = f3() }; // Error, initialization of the return value in f3() // uses a non-constexpr constructor. constexpr void f4(int x) { //...
return type of f1 must be a literal type. return NL(); } constexpr int f2(NL) { // Error, the parameter type NL is not a literal type. return 55; } constexpr S f3() { return S(); } enum { val = f3() }; // Error, initialization of the return value in f3() // uses...
c++ 带有if constexpr的模板化函数中未使用的参数警告出于同样的原因，在被丢弃的分支中不能有语法错误...
问使用constexpr定义并声明const std::array，如果EN前言 const 用于声明一个或多个常量，声明时必须进行...
c++ 带有if constexpr的模板化函数中未使用的参数警告出于同样的原因，在被丢弃的分支中不能有语法错误...
Each of its parameter types is a literal type. (until C++23) It is not acoroutine. (since C++20) Its function body is=default,=delete, or a compound statementenclosingonly the following: null statements static_assertdeclarations typedefdeclarations andaliasdeclarations that do not define classes ...
如果 * 是一个废弃语句，则在 *constexpr中指示一个未执行的分支。此外，自动函数在推导返回类型时只...
// 1.for方法跳出循环 function getItemByIdFor(arr, id) { var item = null; for (var...