2. 函数体内必须有且只有一条 return 语句。 1#include <iostream>2usingnamespacestd;34constexprintnew_sz(inta){5returna;6}78constexprcharnew_char(chars){9returns;10}1112//constexpr string new_str(string s){//错误13//return s;14//}1516intmain(void){17constintfoo = new_sz(10);18cout...
constexpr const char* productName = PRODUCT_NAME; class Newt : public View { private: struct TUIText { #if __cpp_lib_constexpr_string >= 201907L static constexpr const char* title = fmt::format("{} Installer", productName).data(); #else static constexpr const char* title = PRODUCT...
constexpr函数是能够在编译时期计算返回值的函数。如果函数的所有参数都是编译时常量，并且函数体内的计算...
而const修饰变量时该变量既可能在编译期初始化，也可能是在运行期被初始化。const保证的是其所修饰的变...
定义一个指向字符常量的指针，这里，ptr是一个指向 char* 类型的常量，所以不能用ptr来修改所指向的...
定义一个指向字符常量的指针，这里，ptr是一个指向 char* 类型的常量，所以不能用ptr来修改所指向的...
static constexpr char version[] = "GnuTLS(gcrypt)"; return version; } 2 changes: 1 addition & 1 deletion 2 src/metaheader.cpp Original file line numberDiff line numberDiff line change @@ -27,7 +27,7 @@ #include "metaheader.h" #include "string_util.h" static const struct timespec...
Now, what to do with your existing preprocessor macros? You cannot cast the addresses back touintptr_t, because that constitutes areinterpret_cast, which is forbidden in a constexpr context. You can rungcc -E -dMover the header file to extract the macros as an extra build step:...
int main(int argc, char const *argv[]) { static_assert( findlastslash< 6, 6, path >() == 2, "Fail!" ); } Which miserably fails with: clc g++ -o main.exe --std=c++17 test_debugger.cpp test_debugger.cpp: In function ‘int main(int, const char**)’: ...
Cut-down reproducer - replace Examples/test-suite/cpp11_decltype.i with: %module cpp11_decltype %inline %{ struct B { static constexpr const char * should_be_string = "xyzzy"; }; %} Then $ make -s -C Examples/test-suite/go cpp11_decltype...