这是一个经典的问题，涉及到JavaScript中const声明函数和直接使用function声明函数之间的区别。在大多数情况...
// before class struct { constexpr bool empty() const { /* */ } constexpr auto size() const { /* */ } constexpr void clear() { /* */ } }; // after constexpr struct SomeType { bool empty() const { /* */ } auto size() const { /* */ } void clear() { /* */ }...
function (the pointer was passed by value when the function was called), this isn't helpful, as nobody outside the function will be affected by whether you change the pointer or not anyway. Placing the const after a reference is entirely useless and should be avoided. References cannot be ...
might being using ‘&’ because it is going to alter the variable passed to it or it might just be to save copying time and there is no way to tell which it is if the function is compiled in someone else’s library. This could be a risk if one needs to trust the subroutine not ...
foo('before'); // TypeError: foo is not a function{function foo(location) {console.log('foo is called' + location);}}foo('after'); // foo is called after 与函数表达式不会提升到var foo = function(){}一样;{}内部定义的function,不会提升到{}之前。而这正是function的blocking statement ...
function块作用域规则同上: foo('before'); // TypeError: foo is not a function { function foo(location) { console.log('foo is called' + location); } } foo('after'); // foo is called after 与函数表达式不会提升到var foo = function(){}一样;{}内部定义的function,不会提升到{}之前。
Note: IBM supports selected features of C++11, known as C++0x before its ratification. IBM will continue to develop and implement the features of this standard. The implementation of the language level is based on IBM's interpretation of the standard. Until IBM's implementation of all the C++...
error C2143: syntax error : missing ';' before 'constant' error C2440: 'initializing' : cannot convert from 'const char *' to 'char *' error C2440: 'return' : cannot convert from 'const int' to 'int &' error C2664: 'int fprintf(FILE *,const char *,...)' error C2679: b...
Returning by value is safer because you don't have to worry about clients holding onto references after your object has been destroyed, but also because returning a const reference can break encapsulation. Tip Prefer to return the result of a function by value rather than const reference. On ...
(that is, within a single thread of execution, volatile accesses cannot be optimized out or reordered with another visible side effect that issequenced-beforeor sequenced-after the volatile access. This makes volatile objects suitable for communication with asignal handler, but not with another ...